Let Rbe the region in the first quadrant under the graph of y = for 0 SaS V6. 22+2 (a) Find the area of R. x X2 5 Ω (b) If the line x = k divides R into two regions of equal area, what is the value of K? I U x2 X2 5 Ω II II !!! iii

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section: Chapter Questions
Problem 53RE
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Question 1 W
Let Rbe the region in the first quadrant under the graph of y =
for 0 <a S V6.
x²+2
(a) Find the area of R.
x X, 5 C
(b) If the line x = k divides R into two regions of equal area, what is the value of k?
В I
x X2 5
¢
II
123
Transcribed Image Text:Question 1 W Let Rbe the region in the first quadrant under the graph of y = for 0 <a S V6. x²+2 (a) Find the area of R. x X, 5 C (b) If the line x = k divides R into two regions of equal area, what is the value of k? В I x X2 5 ¢ II 123
(b) If the line x = k divides R into two regions of equal area, what is the value of k?
B IU x X, 5 C
三 =
Ω
(c) What is the average value of y =
on the interval 0SeSV6?
x2+2
B IU x X2 5 C
= E 四
II
Transcribed Image Text:(b) If the line x = k divides R into two regions of equal area, what is the value of k? B IU x X, 5 C 三 = Ω (c) What is the average value of y = on the interval 0SeSV6? x2+2 B IU x X2 5 C = E 四 II
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