Let S-((0,-1,1).(0,-2,-1).(1,1.2)}. Which of the following is true?* S is not a basis for R3 S is a basis for R3 because S is linearly dependent O the above is true the above is true S is not a basis for R because S does not span IK R None of these the above is true
Let S-((0,-1,1).(0,-2,-1).(1,1.2)}. Which of the following is true?* S is not a basis for R3 S is a basis for R3 because S is linearly dependent O the above is true the above is true S is not a basis for R because S does not span IK R None of these the above is true
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 45E
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![Let S={(0,-1,1).(0,-2,-1).(1,1.2)} Which of the following is true?
S is not a basis for R?
S is a basis for R
because S is linearly dependent
the above is true
the above is true
S is not a basis for R
because S does not span R
None of these
) the above is true
The set of all polynomial.s of degree 4 under the standard addition and scalar multiplication
operations is not a vector space because"
We can find a polynomial P(x) such that (c+d)P(x)#cP(x)+dP(x).
It is not closed under addition.
We con find](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0a207c83-d3f5-425e-b9cd-ba8e87ee4d5d%2Fc7b2e6bf-421e-47c1-b7aa-12258e8a539e%2Fog51az7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let S={(0,-1,1).(0,-2,-1).(1,1.2)} Which of the following is true?
S is not a basis for R?
S is a basis for R
because S is linearly dependent
the above is true
the above is true
S is not a basis for R
because S does not span R
None of these
) the above is true
The set of all polynomial.s of degree 4 under the standard addition and scalar multiplication
operations is not a vector space because"
We can find a polynomial P(x) such that (c+d)P(x)#cP(x)+dP(x).
It is not closed under addition.
We con find
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