Let S be a subring of the ring R. Thus, by definition (S, +) is an abelian group. Let 0s denote the identity element of this group, and write 0R for the usual "0" of R. Show that 0s = 0R. (See also Exercise 3.54 in Chapter 3 ahead.)

Elements Of Modern Algebra
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Chapter4: More On Groups
Section4.6: Quotient Groups
Problem 31E: 31. (See Exercise 30.) Prove that if and are primes and is a nonabelian group of order , then the...
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Exercise 2.29
Let S be a subring of the ring R. Thus, by definition (S, +) is an abelian
group. Let 0s denote the identity element of this group, and write 0R
for the usual "O" of R. Show that 0s
= OR. (See also Exercise 3.54 in
Chapter 3 ahead.)
Transcribed Image Text:Exercise 2.29 Let S be a subring of the ring R. Thus, by definition (S, +) is an abelian group. Let 0s denote the identity element of this group, and write 0R for the usual "O" of R. Show that 0s = OR. (See also Exercise 3.54 in Chapter 3 ahead.)
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