Let S = { t² + 1, t² – 1, t – 2}. - 2. If S is linearly independent in P2, write 2t2 – t + 5 as a linear combination of the vectors in S.

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A: The solution is follows:

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A: Solution:      If k=1 then (0,0)=-47(3,4)+167(-1,1)+1(4,0)

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