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Let sin 0=u in the equation. Pri 9 sin 20-6 sin 0- 2 = 0 9u? - 6u - 2 = 0 Substitute u for sin 0. The solutions to a quadratic equation in the form au? + bu +c= 0 are shown below. -b+/b? - 4ac 2a u= To use the quadratic formula to solve for u= sin 0, first recognize the values that correspond to a 5, and c in the equation 9u? - 6u - 2 = 0. a = 9, b= - 6, and c = - 2 Solve for u. 1= -(-6)±/(-6) - 4(9)( - 2) u = 2(9) a 0.911 and - 0.244 Now, use u= sin 0 and find the corresponding values of 0. Begin with sin 0= 0.911. 0 = 65.6° and 114.4° (rounded to the nearest tenth)

Let sin 0=u in the equation. Pri 9 sin 20-6 sin 0- 2 = 0 9u? - 6u - 2 = 0 Substitute u for sin 0. The solutions to a quadratic equation in the form au? + bu +c= 0 are shown below. -b+/b? - 4ac 2a u= To use the quadratic formula to solve for u= sin 0, first recognize the values that correspond to a 5, and c in the equation 9u? - 6u - 2 = 0. a = 9, b= - 6, and c = - 2 Solve for u. 1= -(-6)±/(-6) - 4(9)( - 2) u = 2(9) a 0.911 and - 0.244 Now, use u= sin 0 and find the corresponding values of 0. Begin with sin 0= 0.911. 0 = 65.6° and 114.4° (rounded to the nearest tenth)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.3: The Addition And Subtraction Formulas
Problem 60E
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Kindly expound sin theta=.911 means that theta equals 65.6 and 114.4

Let sin 0 = u in the equation. Print 9 sin20 - 6 sin 0 – 2 = 0 9u? - 6u - 2 = 0 Substitute u for sin 0. The solutions to a quadratic equation in the form au? + bu +c = 0 are shown below. - b+ /b? - 4ac u= 2a To use the quadratic formula to solve for u= sin 0, first recognize the values that correspond to a, b, and c in the equation 9u? - 6u - 2 = 0. a = 9, b= - 6, andc= - 2 Solve for u. u = -(-6) +V(- 6)² - 4(9)( – 2) 2(9) * 0.911 and - 0.244 Now, use u = sin 0 and find the corresponding values of 0. Begin with sin 0 = 0.911. e = 65.6° and 114.4° (rounded to the nearest tenth)
Transcribed Image Text:Let sin 0 = u in the equation. Print 9 sin20 - 6 sin 0 – 2 = 0 9u? - 6u - 2 = 0 Substitute u for sin 0. The solutions to a quadratic equation in the form au? + bu +c = 0 are shown below. - b+ /b? - 4ac u= 2a To use the quadratic formula to solve for u= sin 0, first recognize the values that correspond to a, b, and c in the equation 9u? - 6u - 2 = 0. a = 9, b= - 6, andc= - 2 Solve for u. u = -(-6) +V(- 6)² - 4(9)( – 2) 2(9) * 0.911 and - 0.244 Now, use u = sin 0 and find the corresponding values of 0. Begin with sin 0 = 0.911. e = 65.6° and 114.4° (rounded to the nearest tenth)
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