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- Find the new equation of the line y=x after applying the translation by the vector (2, -1). Assuming the +x-axis is horizontal to the right for the vectors in the following figure, find the following scalar products: (a) →A · →C ; (b) →A · →F; (c) →D · →C ; (d) →A · (→F + 2 →C); (e) ^i · →B; (f) ^j · →B; (e) (3 ^i − ^j) · →B, and (h) B^ · B→.Suppose vector a= (4, -6, 10) and vector B= (-6, 9, -15). What is a x b?
- √a. = Find the length of the vector x = 3 -5 5 . Enter 'sqrt(a)' forU'S App -> If the projection of a = î- 2 + 3k on b = 2î+ 1k is zero, then the value of 2 is (A) (B) 1 - 2 (C) 3 - 3 (D) The vector equation of the line passing through the point (-1, 5, 4) anda. A nonzero vector perpendicular to both [-1. 3, 4] and [-2. -1, 3]. b. The distance from (2, -1, 3) to (4, 1, -2) in R^3 c. Find v*w (dot product) such that vector v [-1. 3, 4] and w [-2. -1, 3]