Let Tk (n) denote the value returned by A(k, n). This gives T0(n) = 2 + n, T1(0) = 0, Tk (0) = 1 for k ≥ 2, and Tk (n) = Tk−1(Tk (n − 1)) for k > 0 and n > 0.
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Let Tk (n) denote the value returned by A(k, n). This gives T0(n) = 2 + n, T1(0) = 0, Tk (0) = 1 for k ≥ 2, and Tk (n) = Tk−1(Tk (n − 1)) for k > 0 and n > 0.
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- Find f(1), f(2), f(3), f(4), and f(5) if f(n) is defined re-cursively by f(0) = 3 and for n = 0, 1, 2, ... a) f(n + 1) = −2f(n).b) f(n + 1) = 3f(n) + 7.Given a collection of numbers that might contain duplicates,return all possible unique permutations.For example,[1,1,2] have the following unique permutations:[ [1,1,2], [1,2,1], [2,1,1]]""" def permute_unique(nums): perms = [[]] for n in nums: new_perms = [] for l in perms: for i in range(len(l)+1): new_perms.append(l[:i]+[n]+l[i:]).Modulo arithmeticFor two integers ‘a’ and ‘b’ and a positive integer ‘n’, let + represent the operation a + b = (a+b)mod(n), that is, the result of a + b is the remainder of the usual sum a + b after dividing by n (using a natural representation). Similarly, let * represent the operation a * b = (a*b)mod(n), that is, the result of a * b is the remainder of the product a*b after dividing by n. For example using the set S = {2, 5, 8} and n = 9, 5 + 8 = 4, since 4 is the remainder after dividing 13 (5 + 8) by 9; and 2 * 8 = 7, since 7 is the remainder after dividing 16 (2*8) by 9.a. For each set S and number n specified below, create two “operation” tables (these are called Cayley tables), one showing the results for the operation +, and one showing the results of the operation * for each pair of elements from S (see the example tables in the notes).i. S1 = {0, 1} and n = 2ii. S2 = {1, 2} and n = 3iii. S3 = {0, 2, 4, 6} and n = 8iv. S4 = {1, 3, 5, 7} and n = 8v. S5 = {1, 2, 3, 4} and n =…
- the value of factor(P/F,i,10) can be found by getting the factor values for(P/F,i,4) and(P/f,i,6)and adding it toGiven a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows:If N is an even number, then divide N by two to get a new value for NIf N is an odd number, then multiply N by 3 and add 1 to get a new value for N.Continue to generate numbers in this way until N becomes equal to 1For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1Write code to ask the user to enter a positive integer (N) in the main() function. Write a function sequence()that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequenceconsists of. The returned value must be displayed from the main() function.RSA How do you find a ‘p’ and ‘q’ given a number n and φ(n)? Using x^2 - [n-φ(n)+1]x+n = 0 to find p and q. p and q are relatively prime. n=pq Φ(n) = (p-1)(q-1) Give an Example.
- Consider the following:[Int]$N1 = 2.7[Int]$N2 = 2.7What is the answer for $N1 + $N2 Group of answer choices 4 5 6 2.72.7Let Σn denote the set of all binary strings with lengths less than n. For example, Σ2 = {λ, 0, 1} and Σ3 = {λ, 0, 1, 00, 01, 10, 11} where λ is the empty string, i.e. the string of length 0. For x ∈ Σ we denote the length of x by |x|. a) How many functions f : Σn → Σn are there? b) How many one-to-one functions f : Σn → Σn are there?Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows: If N is an even number, then divide N by two to get a new value for N. If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. Continue to generate numbers in this way until N becomes equal to 1. For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1 Do the following: Write a code in C++ to ask the user to enter a positive integer (N) in the main() function. Write a function sequence() that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequence consists of. The returned value must be displayed from the main() function. Example input and output is given in the following image.
- The binomial coefficient C(N,k) can be defined recursively as follows: C(N,0) = 1, C(N,N) = 1, and for 0 < k < N, C(N,k) = C(N-1,k) + C(N - 1,k - 1). Write a function and give an analysis of the running time to compute the binomial coefficients as follows: A. The function is written recursively.Given two arrays X and Y of positive integers, find the number of pairs such that xy > yx (raised to power of) where x is an element from X and y is an element from Y. Example 1: Input: M = 3, X[] = [2 1 6] N = 2, Y[] = [1 5]Output: 3Explanation: The pairs which follow xy > yx are as such: 21 > 12, 25 > 52 and 61 > 16 .Example 2: Input: M = 4, X[] = [2 3 4 5]N = 3, Y[] = [1 2 3]Output: 5Explanation: The pairs for the given input are 21 > 12 , 31 > 13 , 32 > 23 , 41 > 14 , 51 > 15 . Your Task:This is a function problem. You only need to complete the function countPairs() that takes X, Y, M, N as parameters and returns the total number of pairs. Expected Time Complexity: O((N + M)log(N)).Expected Auxiliary Space: O(1). Constraints:1 ≤ M, N ≤ 1051 ≤ X[i], Y[i] ≤ 103Write a program that reads N from the user and compute the following series: (N-1)-((N-2)^2) /8+ ((N-3)^3) /27-....................+1/N^3