Let V = R. For u, v E V and a E R define vector addition by u Bv:= u + v+2 and scalar multiplication by a u:= au +2a - 2. It can be show nat (V,,0) is a vector space over the scalar field R. Find the following: the sum: 6H6 = 14 the scalar multiple: -9 D6 = -74 the zero vector: Oy = the additive inverse of r: Br

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 11E
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Q1 PART 3

Q2 Part 3 and 4.

Let V = (2, 00). For u, v E V and a E R define vector addition by u Hv:= uv – 2(u+ v) + 6 and scalar multiplication by a Du:= (u- 2)ª + 2.
%3D
It can be shown that (V, , D) is a vector space over the scalar field IR. Find the following:
the sum:
9田10:
58
the scalar multiple:
109
9.
%3D
the additive inverse of 9:
89
-63/3
the zero vector:
Oy
3
the additive inverse of x:
[-3+2x)[-2+x]
Transcribed Image Text:Let V = (2, 00). For u, v E V and a E R define vector addition by u Hv:= uv – 2(u+ v) + 6 and scalar multiplication by a Du:= (u- 2)ª + 2. %3D It can be shown that (V, , D) is a vector space over the scalar field IR. Find the following: the sum: 9田10: 58 the scalar multiple: 109 9. %3D the additive inverse of 9: 89 -63/3 the zero vector: Oy 3 the additive inverse of x: [-3+2x)[-2+x]
Let V = R. For u, v E V and a E R define vector addition by u H v := u + v + 2 and scalar multiplication by a u := au + 2a – 2. It can be
show nat (V, H,O) is a vector space over the scalar field IR. Find the following:
the sum:
6 6= 14
the scalar multiple:
-9 6= -74
the zero vector:
Oy
|
the additive inverse of r:
Transcribed Image Text:Let V = R. For u, v E V and a E R define vector addition by u H v := u + v + 2 and scalar multiplication by a u := au + 2a – 2. It can be show nat (V, H,O) is a vector space over the scalar field IR. Find the following: the sum: 6 6= 14 the scalar multiple: -9 6= -74 the zero vector: Oy | the additive inverse of r:
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