ONone of thesethe above is trueLet W = {(a, b, c, d)| a – 5 b = 0} be a subspace of R. Then a basis for W isO {(1,5,0,0)}O {(1,5,0,0),(0,0,1,0),(0,0,0,1){(5,1,0,0),(0,0,1,0,0,00,1)}{(1,5,0,0).(0,0,0,1)}[1 2 3linint of A is given by:

Let W be subspace of R^4 then we find basis of W

Answered: Let W = {(a, b, c, d)| a – 5 b = 0 } be…

Let W = {(a, b, c, d)| a – 5 b = 0 } be a subspace of R. Then a basis for W is %3D O {(1,5,0,0)} O {(1,5,0,0),(0,0,1,0),(0,0,0,1)} O {(5,1,0,0),(0,0,1,0),(0,0,0,1)} O {(1,5,0,0).(0,0,0,1)}

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Inner Product Spaces

Section5.CR: Review Exercises

Problem 47CR: Find an orthonormal basis for the subspace of Euclidean 3 space below. W={(x1,x2,x3):x1+x2+x3=0}

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Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.

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ONone of these
the above is true
Let W = {(a, b, c, d)| a – 5 b = 0} be a subspace of R. Then a basis for W is
O {(1,5,0,0)}
O {(1,5,0,0),(0,0,1,0),(0,0,0,1)
{(5,1,0,0),(0,0,1,0,0,00,1)}
{(1,5,0,0).(0,0,0,1)}
[1 2 3
linint of A is given by:

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