Let X be a normally distributed random variable with mean 5 and variance 16. Find the following probabilities: 1. P₁ = P(X> 12. 28). 2. p₂ = P(-2.28 < X < 5). 3. P3 P(-2.28 < X < 1.36). = 4. P4 = P(8.64 ≤ X ≤ 12. 28). (P₁, P2, P3, P4) = 0.0344,0.4656,0.1470,0.1470
Let X be a normally distributed random variable with mean 5 and variance 16. Find the following probabilities: 1. P₁ = P(X> 12. 28). 2. p₂ = P(-2.28 < X < 5). 3. P3 P(-2.28 < X < 1.36). = 4. P4 = P(8.64 ≤ X ≤ 12. 28). (P₁, P2, P3, P4) = 0.0344,0.4656,0.1470,0.1470
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 11ECP: A manufacturer has determined that a machine averages one faulty unit for every 500 it produces....
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How were the answers of 0.0344, 0.4656, 0.1470, and 0.1470 attained?
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