Question

Asked Jan 22, 2019

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Let ?(x)=2x2+3x+1.

Find a value of ? between 1 and 5 such that the average rate of change of ?(x) from x=1 to x=5 is equal to the instantaneous rate of ?(x) at x=?.

?=

Step 1

Formula used:

Step 2

Now we have f(x)= 2x^{2}+3x+1, on the interval [1,5], so rate of change is

Step 3

Now evaluate f(5) and f(1):

Sincef(x)= 2x2+3x+1, so

f(5) = 2(25)+3(5)+1 =...

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