Let z be a complex number. Then the solution(s) of sinhz+coshz=1/e is (are) z=2nti-1 where n is an integer. O z=-1 O z=nti-1 where n is an integer. O None of these O does not exist ООО

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter7: Real And Complex Numbers
Section7.3: De Moivre’s Theorem And Roots Of Complex Numbers
Problem 26E
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Let z be a complex number. Then the
solution(s) of sinhz+coshz=1/e is (are)
*
z=2nti-1 where n is an integer.
Z=-1
O z=ni-1 where n is an integer.
O None of these
O does not exist
ООО
Transcribed Image Text:Let z be a complex number. Then the solution(s) of sinhz+coshz=1/e is (are) * z=2nti-1 where n is an integer. Z=-1 O z=ni-1 where n is an integer. O None of these O does not exist ООО
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