Let is = 50e−2t mA, v1(0) = 450 V, and v2(0) = 20 V. 12 μF+is20 μV240 μFDetermine the energy in each capacitor at t= 0.5 s.The energy in each capacitor is as follows:W12 µF|JW20 µF =J

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Answered: Let is = 50e−2t mA, v1(0) = 450 V, and…

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Let is = 50e−2t mA, v1(0) = 450 V, and v2(0) = 20 V.

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter8: Basic Electric Motors

Section: Chapter Questions

Problem 22RQ: What is the unit of measurement for the strength of a...

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.

Question

Let i_s = 50e^−2t mA, v₁(0) = 450 V, and v₂(0) = 20 V.

12 μF
+
is
20 μ
V2
40 μF
Determine the energy in each capacitor at t= 0.5 s.
The energy in each capacitor is as follows:
W12 µF
|J
W20 µF =
J

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