Compare the two image i send, please calculate the true answer. why -(2x+b)=a, can to be x = b-a/2 in cases 2. I mark the problem with red color. This complete question thank u on the previous Question me In bartleby, the expert Solvethe two ase from equation. But after I write again,In the case 2 me and the expert is different.ThisColtefromCaseme12xth1 = aCase 12xtb 2 a2xtb = ax = a-b2Case 212x tb co= (2xth) = 9- 2x - b = aX 2atb.-2x = -a-b-a-bJwiththis different from the expert,How, Case is true In Case 2i case Let's first simplify the equation |2x + b =Case 1: 2x + b>0In this case, 2x + b = 2x + b,so the equation becomes 2x + b = a,which can be rearranged to solve for x asX =a-b2(1)...Case 2: 2x + b < 0In this case, 2x + b == a by considering two cases:(2x + b),- (2x + b) = a,so the equation becomes :which can be rearranged to solve for x asX =b-a2. (2) 20Why don't, x=-a-b

The equation provided, is .To find:The value of .Concept used:The absolute function is defined as

Let's first simplify the equation |2x + b = a by considering two cases: Case 1: 2x + b>0 In this case, 2x + b = 2x + b, so the equation becomes 2x + b = a, which can be rearranged to solve for x as . (1) x = a-b 2 ***..... Case 2: 2x + b < 0 In this case, 2x + b = - (2x + b), - (2x + b) = a, which can be rearranged to solve for x as x = so the equation becomes : b-a 2 (2) ? Why don't, X = -a-b 2