Let’s try this calculation, assuming we have an array of size 10. If rear is currently 5, it will be set to 6%10, or 6. If rear is currently 9, it will be set to 10%10 or 0. Try this calculation using various situations to see that it works no matter how big the array is
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Let’s try this calculation, assuming we have an array of size 10. If rear is currently 5, it will be set to 6%10, or 6. If rear is currently 9, it will be set to 10%10
or 0. Try this calculation using various situations to see that it works no matter
how big the array is
Step by step
Solved in 2 steps
- Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {You can see in the above display, we first sort each row of the 2D array; we then take the transpose of a two D array, i.e., all the row elements becoming the column elements; we then sort each row of the 2D again. If you read the final array, each row is sorted; each column is also sorted. The smallest element obviously is the 1st element of the two D array and the last element is the largest element of a two D array. Let us now look at the following UML diagram: (Note that additional methods are allowed; proposed methods and instance variable cannot be changed) Main method firstly constructs a 2D array of certain sizes and then construct a TwoD object and drive the task according to the above runtime interactions and displays. TwoD class has only one instance variable which is a two D array of numbers ( int or double). The constructor must do some “deep” copying. A copy constructor. The other three methods are obvious in definition: to sort each row, to rotate the 2D array (i.e.,…Write a program to ask the user for the number of arrays he wants to maintain and then populate eacharray by taking elements from the user. Merge all these arrays in another array and finally remove duplicateelements from the merged array.
- Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example:(in java) Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {Write a program that first reads an integer for the array size, then reads numbers intothe array, and finally outputs how many numbers have values that are greater than theaverage. For practice reasons, try not to use the index notation of arrays (e.g. myarray[i])at all. Use pointers instead.Below is your exercise for Basic Sorts. For submitting your answers, you can either send me an updated Word document with your answers, email your answers directly, or even take a screen shot of your work on paper if you like. In all cases, email me your answers when you feel ready. Use the following array of numbers for each of the sorting tasks below: 6 2 8 1 7 5 3 4 Bubble Sort (not optimized) – show what the array looks like each time the swap operation is performedusing the bubble sort algorithm (not optimized, meaning no use of swapFlag) Selection Sort - show what the array looks like each time the swap operation is performed using the selection sort algorithm Insertion Sort – show what the array looks like at the end of each outer loop iteration of the insertion sort algorithm
- Suppose that you are playing a card game whose goal is to collect exactly k cards with a total value of t. Write a solution that can determine if it is possible for a given collection of cards whose values are given in the array values. For example, if the array contained the values <10,5,7,2>, k = 3, and t = 12, you would return false because no three values add to 12. However, if t = 14, you would return true, since 5 + 7 + 2 = 14. So I considered this to be a form of groupSum recursion, so I try to implement it in recursion form. However, since the passing parameters are not the incrementing level index but 'k' that is the limit number of the numbers we can choose from the array, I cannot use passing index through recursion to search from the start of the array toward the end of the values.length(the length of the array). would there be any method I can use to increment and search along the array using k, the number of numbers we can add into the total(t) instead of the…Allocate the memory at runtime to store 10 integer numbers and ask values from the user. Now, create another array of same size and fill the elements based on the processing of elements in the first array as follows: If the number at any location is prime, then store ‘P’ at the same location in second array If the number is not prime but if it is even, then store ‘E’ In case above conditions are not true, then store ‘N’What will be the problem with the following algorithm for finding an item in an unsorted array? How can you solve it? int location = 0; bool moreToSearch = (location > length); found = false; while (moreToSearch && !found) { if(item == info[location]) { item = info[location]; } else { location++; moreToSearch = (location > length); } }
- You have an array with all the numbers in it, starting at 1 and going up to a maximum of 32,000. You don't know what N is, and the array could include duplicate elements. How would you publish every duplicate entry in the array if you had just 4 kilobytes of memory?You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent houses have a security system connected, and it will automatically contact the police if two adjacent houses were broken into on the same night. Given an integer array nums representing the amount of money of each house, return the maximum amount of money you can rob tonight without alerting the police. Example 1: Input: nums = [2,3,2] Output: 3 Explanation: You cannot rob house 1 (money = 2) and then rob house 3 (money = 2), because they are adjacent houses.Please code in python.Given an array of integers a of even length, your task is to split it into two arrays of equal length such that all the numbers are unique in each of them. There may be more than one possible answer, in which case you may return any of them. If there are no possible answers, return an empty array. Hint: Count the number of occurrences of each integer in a. If there are integers occurring more than twice, then there is no solution. Next, put the integers occurring twice into both answer arrays. Finally, put all other numbers in the answer arrays, following the condition that they should have equal sizes. Example • For a = [2, 1, 2, 3, 3, 4], the output can be solution(a) = [[2, 1, 3], [2, 3, 4]]. Answers like [[1, 2, 3], [2, 3, 4]] or [[4, 2, 3], [3, 2, 1]] would also be considered correct. • For a = [1, 2, 2, 1], the output can be solution(a) = [[1, 2], [2, 1]]. Again, there are other possible answers. • For a = [2, 2, 3, 3, 2, 2], the output should be solution(a)…