lim ( = ) (-1)" n+5 O 1 O -1 O -2 O 2

Q: 10. If n is a positive integer, then lim n- 0o N + (1/n)" 1+(2/n) can be expressed as + ... (A) |dx…

A:

Q: lim z?= 1 0 2 0 -2 O -1 0

A: To find limz→iz2.

Q: О А. НО: р 0.1

A: p = 26/349 =0.07   population proportion = 0.1

Q: За - 2 lim x3 - 1 O 2 O does not exist 13 8.

A: lim      (3x-2)/(x3 -1) x -- ∞ here ∞/∞ form so we use la hospital rule we differentiate above and…

Q: れ ポ+n3 lim (nj)2 + n4 j=1 n-00

A:

Q: nt b n+30 n+3 lim e + e nn+3 nn+3n

A:

Q: 1 lim x→-∞ ex Select the correct response: O +0 O 1

A:

Q: lim (1,y) (0,0) (3 + (2² + y²) In(æ² + y?)) O 00 O 3 O does not exist 0 1

A: To find : limx, y → 0, 0 3 + x2 + y2 lnx2 + y2

Q: n+1 2n +3 lim 2n +1

A:

Q: 1-e* lim *0+ 2x2 - 00 None of these 1 8. O O O

A:

Q: X – 4 | lim х-4 х2 — х — 12 O 4/7 O undefined 1/7

A:

Q: 4n+1 b] lim %3D n+3

A:

Q: Lim Vn' +n

A: Explanation of the answer is as follows

Q: lim z+0 z2 - 2sinz + 2x O 1 O 12 O 0 O 20

A: Let L is the limit value of given function .

Q: sin(n!) lim n→00 n2 +7

A:

Q: 2n + 6 an %3D 5n lim an DNE n- 00

A: Given query is to find sequence converging or diverging.

Q: 1 lim 1+ n 1 + 2 + n 1 +...+ n→∞ п +n, : =?

A: first, calculate the sum of the series then find the limit of the given problem as following:-

Q: (-1)" (i) lim n 00 = 0. (ii) lim = 0. %3D %3D sin n (iii) lim n-00 n2 1 (iv) lim n 0o n! = 0. = 0.

A: Given: limn→∞1n=0 limn→∞(-1)nn=0 limn→∞sin nn2=0

Q: 71. lim = 0 n+00

A: Given: limn→∞1n4+n8=0 we have to prove this for this we solving L.H.S taking n8  common

Q: lim x16 x → 0 x2 – 2sinx +2x O 272 O 240 о 1

A: we will solve this using L'Hospitals rule.

Q: 4 Find Lim x-0 2e* – 12 А. В. C. - 0.4 D. 0.5 Select one: O A O C O D NIN 13

A:

Q: 2n +3 lim 4n+1 =? n O A e O B. e O D. 00

A: From the given problem:   limn→∞2n+3n4n+1   Let,   y=limn→∞2n+3n4n+1   Now taking log on both sides…

Q: n |2n lim n→0 Vm²

A:

Q: 2n n+1 lim n A) e

A: Given,            limn→∞n+1n2n

Q: 24. lim xsin- is 110 (A) 0 in(s (B) ∞ (C) nonexistent (D) - 1 (E) 1

A:

Q: Evaluating limits Evaluate the following limits, where c and kare constants.

A: "Since you have asked multiple questions we will solve the first question for you. If you want any…

Q: Find the limits

A: Limit:      n→∞lim1n(e1n+e2n+.....+en-1n+enn)= n→∞lim1n∑r=1∞ ern

Q: lim N-81 o1 21 O 18 O 1 18

A: Given:     To determine: the value of the given limit

Q: a) ) (tan¬'(n+ 1) – tan-1n Σ n=1 2n+1 b) 32n+1 n=1 2n +3 ) Σ 5n +1 n=1

A: To find whether the series converges or diverges and also their sum .

Q: Find -x-1 lim 1-0 I² O does not exist O-1/2 O 0 O 1 O 1/2 O Other:

A:

Q: 17. lim (Vn² +n – /n? +1) = } n00

A: To show: limn→∞ n2+n-n2+1=12

Q: lim exp is 1. (e* - e) 2. (e* -). 3. (e* - e²). 4. None of the above O 1 O 4 3.

A:

Q: 1-e¬* lim x→0+ 2x2 -00 00 None of these O 1

A: We need to evaluate limx→0+1-e-x2x2 = 1-e-02(0)2 = 1-10= 00 Hence we will use L Hopital's rule It…

Q: 1-e-* lim x→0+ 2x2 -00 00 O None of these 1 || O O O

A:

Q: 10-n lim n-00 Vn+ 10 + Vn2+n A)

A:

Q: 1-e* lim *0+ 2x2 -00 00 O None of these 1 O O O O

A: The given expression is limx→0+1-e-x2x2.

Q: 17. lim n00 10n + 12 10 +0

A: Given- limn→∞n10n+12=110 To prove- The above statement.

Q: Find the limit

A: limx→∞2x-1x+1

Q: x.2* 15. lim x-0 2*-1 (A) In 2 (В) 1 (С) 2 1 (D) 1n 2

A:

Q: x° – 27 lim %3D x-3 D - 27 O 18 O27

A: The given expression is limx→3x3-27x-3.

Q: lim (n + 1 – Vn² n) n 00

A: Given query is to find indicated limit.

Q: lim (2n + 1)´ 2 n→ 00 п +1

A:

Q: 43. lim 21/" = 1 n00

A: Given limits limn→∞21n=1 Taking L.H.S of the given limit limn→∞21n Apply the limit n=∞…

Q: 2n + 1 2 1) Use e - N to prove lim n0 5n + 2

A:

Q: 9x +6 lim 5x O a. 9 5 O b. 1 5 O CO O d. 9

A:

Q: Зx2 — 5х — 2 lim x→2 In(x – 1) - is | (А) 7 (В) 8 (С) е2 (D) 0 O A O B ос O D

A: Given: limx→23x2-5x-2lnx-1 To find the value of the given expression 3x2-5x-2lnx-1 where x…

Q: limn→0 E-1 3(1+ k=1 n O 10 O 8 O 78 O 26

A: Answer is :  26 Summation of series with the help of integration: By the definition of of integral…