lim f(T) = 1, lim f(r) = – 00, I -2 f(-2) = %3D 4- 3- -5 -4 -3 -2 A1 2 3 4 -2 -3- -4-

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A: 3x2+2y2dx+4xy+6y2dy it is of the form     Mdx+Ndy=0where M=3x2+2y2   , N=4xy+6y2∂M∂y=4y∂N∂x=4y ⇒∂M∂y...

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A: Given differential equation can be writen as, (D2+2D+5)x=8e-t.....(i)d=ddt, x(0)=0...(ii),dxdt|t=0=8...

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Q: solve

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A: We can find the answers as below in support of the above question.  

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