Liquid ammonia at 270K is compressed from its saturation pressure of 381 kPa to 12,000 kPa. For saturated liquid ammonia at these conditions: V = = 1.551 10 -3 m3 kg B= 2.095* 10-3 K-1 K = 4.53 10 5bar-1 * Assume the ammonia is an incompressible fluid. What is the change in enthalpy in J/mol? J What is the change in entropy in ? mol-K What is the temperature after compression in Kelvin?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Liquid ammonia at 270K is compressed from its saturation pressure of 381 kPa to 12,000 kPa.
For saturated liquid ammonia at these conditions:
V = 1.551 * 10-3 m³
kg
B= 2.095 * 10-³ K-1
k = 4.53 * 10-5 bar -1
Assume the ammonia is an incompressible fluid.
What is the change in enthalpy in J/mol?
What is the change in entropy in
J
mol-K
?
What is the temperature after compression in Kelvin?
Transcribed Image Text:Liquid ammonia at 270K is compressed from its saturation pressure of 381 kPa to 12,000 kPa. For saturated liquid ammonia at these conditions: V = 1.551 * 10-3 m³ kg B= 2.095 * 10-³ K-1 k = 4.53 * 10-5 bar -1 Assume the ammonia is an incompressible fluid. What is the change in enthalpy in J/mol? What is the change in entropy in J mol-K ? What is the temperature after compression in Kelvin?
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