· Locate the centroid and compute for the moment of inertia of the following section wrt X-X. Use metric units. /2" [13 mm] %3D 5 [125 mm] 2" * [13mm] 3" [75 mm] (b)
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- The equation of the catenary shown is y = 100 cosh (x/100) where x and y are measured in feet (the catenary is the shape of a cable suspended between two points). Locate the y-coordinate 0f the centroid of the catenary by numerical integration using x=25ft.Draw the Orthographic projection of the given isometric view Mention the view Mention the dimensions Note : use CREO prametric 3.0Let XYZ = 728
- Q1. A line RS of 55 mm in length is inclined to HP by 30o and parallel to VP. One of its end points is above HP by 20 mm and in front of VP by 30 mm. The line is in single quadrant. Find the projections of the line RS and find out its horizontal trace.A centroid is an object's geometric center. For an object of uniform composition, its centroid is also its center of mass. Often the centroid of a complex composite body is found by, first, cutting the body into regular shaped segments, and then by calculating the weighted average of the segments' centroids.An object is made from a uniform piece of sheet metal. The object has dimensions of a = 1.05 ft , where a is the diameter of the semi-circle,b = 3.74 ft , and c = 2.45 ft . A hole with diameter d = 0.700 ft is centered at (0.925,0.525) . Part A Find the area of the body. (Figure 1) Express your answer numerically in feet squared to three significant figures. Part B Find x¯ , the x -coordinate of the body's centroid. (Figure 1) Express your answer numerically in feet to three significant figures. Part C Find y¯ , the y -coordinate of the body's centroid. (Figure 1) Express your answer numerically in feet to three significant figures.As shown, a section of a roller coaster track (Figure 3) follows the form of y=(2/3)x1.5 . Locate the centroid x¯ of the track between x=0 m and x=4m . Express your answer numerically in meters to three significant figures.
- For the given area of 10 cm 2, the moment of inertia about axis 1 is 708 cm4. When d1 = d2 = 2 cm, the moment of inertia about axis 3 (the centroidal axis) will be ___________ cm4. Calculate your answer to 1 decimal place.d) moment of inertia about the horizontal centroidal axis for transformed CFRP. Enter your answer in mm4 to 2 decimal places.the centroidal moments of inertia (ĪTX and ĪTY) of the entire figure.
- Tower 1 - 300 km 15° EastofNorth @ 2:50 AM; Tower 2 - 250 km North @ 2:30 AM; and Tower 3 - 283 km (~200√2 km) 45° Northeast @ 2:00 AM. Using geometric constructions only: 4. Using the information from towers 1 and 3 as reference, what is the average speed of the fighter jet?_____________Please use a ruler. Scale: 100km = 1cm. Please show and explain the complete process.22 - Constant thickness homogeneous planar plate in the figure coordinates of the center of gravity M (Xm, Ym) of the surface area, Find it on the (x, y) set. t = 7 cm and a = 14 cm. Find the x-axis coordinate (Xm) of the center of gravity of this planar plate.A) 14B) 17C) 13D) 16E) 15Figure (a) shows the cross section of a column that uses a structural shape known as W867 (wide-flange beam, nominally 8 in. deep, weighing 67 lb/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following cross-sectional properties: A=19.7in.2,Ix=272in.4, and Iy=88.6in.4. Determine the dimensions of the rectangle in Fig. (b) that has the same Ix and Iy as a W867 section.