Explain the maths O. LT. F=1253+452+2s+1M=-1V(1-4w²)²+(2w³+2w)²1(1–4(0.6435)²)´+(2(0.6435)+2x0.6435)=0.516GM=1%3DM0.516=1.932w3+2wPM=tan-1-4w22x0.64353+2x0.6435=t an-11-4x0.64352=-70. 16°

Answered: M=- (1-4w²)²+(2w³+2w)² 1…

M=- (1-4w²)²+(2w³+2w)² 1 (1-4(0.6435)²)²+(2(0.6435)³ +2x0.6435)“ =0.516 GM=1 M 0.516 =1. 93 PM=tan- 1 2w3+2w 1-4w2 -1 =t an 2x0.6435+2x0.6435 1-4x0.6435² =-70. 16°

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.4: Fractional Expressions

Problem 65E

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Question

Explain the maths

O. LT. F=
1
253+452+2s+1
M=-
1
V(1-4w²)²+(2w³+2w)²
1
(1–4(0.6435)²)´+(2(0.6435)+2x0.6435)
=0.516
GM=1
%3D
M
0.516
=1.93
2w3+2w
PM=tan-
1-4w2
2x0.64353+2x0.6435
=t an-1
1-4x0.64352
=-70. 16°

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