M IS golng a circular motion in a path of radius R as shown in Figure 7. The gravitational force acts on the block. Assuming that a friction force of magnitude f = b0²/3 also acts on the block where b is a constant and 0 is the angle with the horizontal as shown in Figure 7 (g is the gravitational acceleration), find the speed of the block when the block is at 0 T/6 angular position (sin(r/6) 1/2 and cos(T/6) = v3/2).

icon
Related questions
Question
Select one:
V9R –
6bR ,™
)5/3
5m '6
9bR ,T
(~)2/3
10m '6
V9R
gR –
VaR
gR -
6m 5/3
5bR T
-)5/3
106R 3/2
gR –
9m '6
V9R
5bR ,T
gR –
6m 63/5
Transcribed Image Text:Select one: V9R – 6bR ,™ )5/3 5m '6 9bR ,T (~)2/3 10m '6 V9R gR – VaR gR - 6m 5/3 5bR T -)5/3 106R 3/2 gR – 9m '6 V9R 5bR ,T gR – 6m 63/5
Question 13: A block of mass M is released at rest and it is under going a
circular motion in a path of radius R as shown in Figure 7. The gravitational
force acts on the block. Assuming that a friction force of magnitude f = b0²/3
also acts on the block where b is a constant and 0 is the angle with the horizontal
as shown in Figure 7 (g is the gravitational acceleration), find the speed of the
block when the block is at 0 = 1/6 angular position (sin(7/6) = 1/2 and
%3D
cos(7/6) = v/3/2).
m
R
f
Figure 7
Transcribed Image Text:Question 13: A block of mass M is released at rest and it is under going a circular motion in a path of radius R as shown in Figure 7. The gravitational force acts on the block. Assuming that a friction force of magnitude f = b0²/3 also acts on the block where b is a constant and 0 is the angle with the horizontal as shown in Figure 7 (g is the gravitational acceleration), find the speed of the block when the block is at 0 = 1/6 angular position (sin(7/6) = 1/2 and %3D cos(7/6) = v/3/2). m R f Figure 7
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer