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M8 3k Σ k=0 ³√/K³ +2 elect the correct choice below and fill in the answer box to complete your choice. Type an exact answer.) OA. The series is a geometric series with common ratio OB. The series is a geometric series with common ratio 3k k→∞ √k³. C. Because lim +2 . This is greater than 1, so the series diverges by the properties of a geometric series. . This is less than 1, so the series converges by the properties of a geometric series. the series converges by the Divergence Test.

M8 3k Σ k=0 ³√/K³ +2 elect the correct choice below and fill in the answer box to complete your choice. Type an exact answer.) OA. The series is a geometric series with common ratio OB. The series is a geometric series with common ratio 3k k→∞ √k³. C. Because lim +2 . This is greater than 1, so the series diverges by the properties of a geometric series. . This is less than 1, so the series converges by the properties of a geometric series. the series converges by the Divergence Test.

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter8: Sequences And Series
Section: Chapter Questions
Problem 6CC
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Determine whether the following series converges. Justify your answer.

∞ Σ k=0 3k D. 3/, 3 k + 2 Select the correct choice below and fill in the answer box to complete your choice. (Type an exact answer.) A. The series is a geometric series with common ratio B. The series is a geometric series with common ratio Because lim k→∞ 3 Because lim k→∞ 3 3k 3 k + 2 3k 3 k + 2 = = This is greater than 1, so the series diverges by the properties of a geometric series. This is less than 1, so the series converges by the properties of a geometric series. the series converges by the Divergence Test. " " the series diverges by the Divergence Test.
Transcribed Image Text:∞ Σ k=0 3k D. 3/, 3 k + 2 Select the correct choice below and fill in the answer box to complete your choice. (Type an exact answer.) A. The series is a geometric series with common ratio B. The series is a geometric series with common ratio Because lim k→∞ 3 Because lim k→∞ 3 3k 3 k + 2 3k 3 k + 2 = = This is greater than 1, so the series diverges by the properties of a geometric series. This is less than 1, so the series converges by the properties of a geometric series. the series converges by the Divergence Test. " " the series diverges by the Divergence Test.
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