Marcia makes jewelry to sell at the artists' fair. She spends $120 to rent a stall at the fair for the day and each piece of jewelry costs Marcia $15 in materials. Which equation would compute the number of pieces of jewelry Marcia must sell at the artists' fair such that the average cost per piece of jewelry would be $20? 120 20 = 15x 20 = x+ 120 C 20 = 15x 15x+120 20 =
Marcia makes jewelry to sell at the artists' fair. She spends $120 to rent a stall at the fair for the day and each piece of jewelry costs Marcia $15 in materials. Which equation would compute the number of pieces of jewelry Marcia must sell at the artists' fair such that the average cost per piece of jewelry would be $20? 120 20 = 15x 20 = x+ 120 C 20 = 15x 15x+120 20 =
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter1: Introduction To Algebra
Section1.7: A Problem Solving Plan
Problem 12P
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Transcribed Image Text:Multiple Choice. Solve each of the following problems, using the available space for
scratch work. After examining the form of the choices, decide which is the best of the
choices given and fill in the corresponding circle on the answer sheet. No credit will be
given for anything written in the exam book.
9. Marcia makes jewelry to sell at the artists' fair. She spends $120 to rent a stall at
the fair for the day and each piece of jewelry costs Marcia $15 in materials.
Which equation would compute the number of pieces of jewelry Marcia must sell at
the artists' fair such that the average cost per piece of jewelry would be $20?
120
20 =
20 = 15x
%3D
x+120
20 =
15x
15x + 120
20
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