Mary is shopping for houses in the neighborhood.  20 of the houses are between $60,000-$70,000; 30 of them are $80,000-$90,000; 20 of the houses are between $91,000-$110,000; and 30 of the houses are above $120,000.  If Mary is debating between two houses, one that is $80,000-$90,000 and another that is $91,000-$110,000, what are the number of ways that Mary can select houses?

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter10: Systems Of Equations And Inequalities
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Mary is shopping for houses in the neighborhood.  20 of the houses are between $60,000-$70,000; 30 of them are $80,000-$90,000; 20 of the houses are between $91,000-$110,000; and 30 of the houses are above $120,000.  If Mary is debating between two houses, one that is $80,000-$90,000 and another that is $91,000-$110,000, what are the number of ways that Mary can select houses?

Expert Solution
Step 1

Given data

Price Range

No of Houses

$60,000 -$70,000

20

$80,000 -$90,000

30

$91,000 -$110,000

20

Above $120000

30

 

No of houses Mary can select in the range of $80,000 -$90,000 = 30

No of houses Mary can select in the range of $90,000 -$110,000 = 20

Total no of ways Mary can select the Houses = 30 x 20 = 600

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