Match the solution curve with one of the differential equations. O y" + 4y = 0 O y" + 2y' + y = 0 O y" + y = 0 O y" – 2y' – 3y = 0 О у" - 7y' + 12y %3D 0 O y" + 2y' + 2y = 0 Explain your reasoning. (Assume that k, k1, and k2 are all positive.) O The auxiliary equation should have a repeated negative root, so that the solution has the form cje-kx + c2xe-kx. O The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form ex(cị cos ßx + c2 sin ß> O The differential equation should have the form y" + k2y = 0 where k = 1, so that the period of the solution is 27. O The auxiliary equation should have one positive and one negative root, so that the solution has the form czekix + cze¬k2x. O The differential equation should have the form y" + k2y = 0 where k = 2, so that the period of the solution is n. O The auxiliary equation should have two positive roots, so that the solution has the form cjek1X + c>ek2*.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Match the solution curve with one of the differential equations.
y" + 4y = 0
О у" + 2y' + у %3D 0
O y" + y = 0
O y" – 2y' – 3y = 0
О у" - 7y' + 12у %3D 0
y" + 2y' + 2y = 0
Explain your reasoning. (Assume that k, k1, and k2 are all positive.)
O The auxiliary equation should have a repeated negative root, so that the solution has the form cje-kx + c2xe¯kx.
The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form e"x(c1 cos Bx + c2 sin Bx).
The differential equation should have the form y" +
k?y
= 0 where k = 1, so that the period of the solution is 2n.
O The auxiliary equation should have one positive and one negative root, so that the solution has the form cqek1× + c2e¬k2×,
The differential equation should have the form y" + k2y = 0 where k = 2, so that the period of the solution is n.
O The auxiliary equation should have two positive roots, so that the solution has the form c1eki× + c2ek2×.
Transcribed Image Text:Match the solution curve with one of the differential equations. y" + 4y = 0 О у" + 2y' + у %3D 0 O y" + y = 0 O y" – 2y' – 3y = 0 О у" - 7y' + 12у %3D 0 y" + 2y' + 2y = 0 Explain your reasoning. (Assume that k, k1, and k2 are all positive.) O The auxiliary equation should have a repeated negative root, so that the solution has the form cje-kx + c2xe¯kx. The auxiliary equation should have a pair of complex roots a ± ßi where a < 0, so that the solution has the form e"x(c1 cos Bx + c2 sin Bx). The differential equation should have the form y" + k?y = 0 where k = 1, so that the period of the solution is 2n. O The auxiliary equation should have one positive and one negative root, so that the solution has the form cqek1× + c2e¬k2×, The differential equation should have the form y" + k2y = 0 where k = 2, so that the period of the solution is n. O The auxiliary equation should have two positive roots, so that the solution has the form c1eki× + c2ek2×.
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