Matlab Code % Problem Statement - The area under a curve can be estimated by breaking% the x-axis into increments, evaluating the function at a point inside% that increment, and approximating the area under the curve in that% increment as a rectangle. %% Housekeeping Commands clcclear%% Variables to be used% Inputs% Xmin - the minimum limit of the range% Xmax - the maximum limit of the range% Outputs% area - the final approximation of the area under the curve for the given range%% Inputs% This generates the scalars, Xmin and Xmax, with random values which will be used to evaluate your code% Xmin=randi(5)% Xmax=Xmin+randi([5 10])% Test Case 1Xmin = 0;Xmax = 10;% Test case output:% area = 131.3823%% Start Programming Problem StatementThe area under a curve can be estimaled by breaking the x asis into increments, evakualing the luncian at a point insice that incrament, and approximating the area under the curve in that incrament as areclangke. The igure below shows this approximalion with an incronent el 1 and the tunclion being evaluabed al he midpaint of he increment.As the increment deoreases, the approsimation of the aren undor the ourve improves as shown when the ineroments are deereased to 0.25 for the same tunetion as shown abeve.Wto the code hat will calculate the area under the curve:Vina)+ 0.5-(wheru x is in radiansusing decreasing increments until the aren value converges (the difference between the area from two onsecutive runs is less than 0.01%). Use the midpoint approximation method and start with an incrementof 1. Decrease the increment by half every iteration. StartdePine termsinc set to oneSlope I- calculate using definte loop fron FaSlope2 sct to zeroinitialize aCounter52=D0%3D2 =4(use indetante / elagel slapehloopslapel slopeh(diffrence > 0.01%6divide inc by 2S=4552=45$z=4.27ol farsl fimeCheck:fset slopel eqyak to slape?Use a defnide loop fam Fato find the slopeCourtler not zcrerecatautte s tope2increpent the ConterUsang nen inclend

MATLAB code to copy: syms x % declaring x as symbolicy = 8*sin(x) + 0.5*x.^2 - x; % function…

Answered: Matlab Code % Problem Statement - The…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Matlab Code

% Problem Statement - The area under a curve can be estimated by breaking
% the x-axis into increments, evaluating the function at a point inside
% that increment, and approximating the area under the curve in that
% increment as a rectangle.

%% Housekeeping Commands
clc
clear

%% Variables to be used
% Inputs
% Xmin - the minimum limit of the range
% Xmax - the maximum limit of the range

% Outputs
% area - the final approximation of the area under the curve for the given range

%% Inputs
% This generates the scalars, Xmin and Xmax, with random values which will be used to evaluate your code
% Xmin=randi(5)
% Xmax=Xmin+randi([5 10])
% Test Case 1
Xmin = 0;
Xmax = 10;
% Test case output:
% area = 131.3823

%% Start Programming