Max. Z= 12X, + 14X2 Subject to: 2X, + 3X2 s 24 (Constraint of raw material R1) 2X1 + X2s 16 (Constraint.of raw material R2) X1s 7 (Demand for product X1) X1 X2 2 0 1- By using the Algebraic Analysis find whether a change in the right- hand side for constraint of raw material R2, (16), and the current basis remains optimal.

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