If the two tensions T1 = 200 - 400 N and T2 = 300 - %3D 500 N act at B, determine the resultant produced by these tensions. 1m B m C
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A: Given Data: The distributed load-1: w1(x)=100x2. The distributed load-2: w2=400 N/m.
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Q: Q1. Determine the resultant moment +be fig show n below: 200N 70 8OON 1.
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Q: D FDA= 3.5 kN, 9 m FDB= 2.5 kN FDc= 3.0 kN B 4.5 m 3 m 3 m 3 m A - 30°
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Q: y 500 N 300 mm 500 N 500 N
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Q: Q1. Determine the resultant moment +be fig. show n below: 200N 3 m 70 アア
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- The string attached to the kite weighs 0.4 oz/ft. If the tension in the string is 2.8 lb at O and 3.2 lb at B, determine the length s of the string and the height H of the kite.The intensity of the distributed load acting on the beam is w = 3.1 kN/m . Determine the magnitude of reaction at A and the x and y components of reaction at B using scalar notation.The pipe has a mass of 12 kg>m. If it is fixed to the wall at A, determine the resultant internal loadings acting on the cross-section at B.
- Draw the free body diagram and determine all the reationGiven that the PE at A is 20 kJ and KE at A is 5.0 kJ. What is the KE at B if the height at B is 2.0 m? (mass= 1000kg)The cylinder having a diameter 2.5 ft weighs 57 lb and is 6 ft long. Determine the reaction (lb.) at A neglecting friction. Determine the reaction at B (lb.) neglecting friction. Weight density of water is 62.4 lb/ft3 Sp.gr Gs = 1.6
- The pipe has a mass of 12 kg/m. If it is fixed to the wall at A, determine the resultant internal loadings acting on the cross section at B.The pole is subjected to the force F which has components Fx = 1.6 kN and Fz = 1.35 kN. If β = 72, determine the magnitude of Fy and FBased on the information given on the free body diagram , find the value of Ax, Ay and N.
- Since the system is in static equilibrium, find the forces that occur in AB and AC ropes.g = 9.81 m / s2Determine the intensity and position of the resultant R lf two forces F1 and F3 and torque M that acts on the metal profile given as in the figure,if: F1= 2kN a=2,10m F2= 5kN b=2,10m M=24kNm c=3,10mthe man is holding up the 35-kg ladder ABC by pushing perpendicular to ladder. The total length of the ladder is AC=6m. If maximum force that the man can exert is 400N at B which is 2m from A. determine the smallest angle, theta, at which the man can support the ladder