Merge two arrays of integers Ex: Int[] arr1 = {1,2,3,4}; Int[] arr2 = {5,6}; Output: Arr3 = {1,2,3,4,5,6
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Required code in java
![Merge two arrays of integers
Ex:
Int[] arr1 = {1,2,3,4};
Int[] arr2 = {5,6};
Output:
Arr3 = {1,2,3,4,5,6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5e5680c-bff7-46c3-baeb-801e776a5f69%2F1a19da83-b1b9-4dfa-a0ab-1fe9bf47e7b9%2Fzlt0ltq_processed.jpeg&w=3840&q=75)
Step by step
Solved in 4 steps with 2 images
- in java Create two arrays with same length n: - Array A with integer numbers that user will insert- Array B with random numbers from 0 to 100.- Find sum of both arrays,- Find maximum values of both array and compare them: .if maximum of 1 st is lower then maximum of 2nd array: print sums of both arrays.if maximum of 1st is greater then maximum of 2nd array print 2nd array (use println)otherwise print first array in reverse.in java Integer numElements is read from input, representing the number of integers to be read next. Then, the remaining integers are read and stored into array valuesArray. For each element in valuesArray that is divisible by 9, assign the element with the element's current value plus 1. Ex: If the input is: 3 81 99 30 then the output is: Original values: 81 99 30 New values: 82 100 30 Note: (x % 9 == 0) returns true if x is divisible by 9. 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 for (i=0; i<valuesArray.length; ++i) { valuesArray[i] =scnr.nextInt(); } System.out.print("Original values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); /* Your code goes here */ System.out.print("New values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); } }Consider 2 integer arrays, x and y, each with size equal to 10.Initialize array x with random numbers between 1 and 100.Write code that fills array y with values such that each element of y is the corresponding valueof x multiplied by its index.
- Suppose you have two arrays A and B of equal size N with completely filled unsorted? Display all elements which are common in A & B.For an array declartion of int number [25];, what will be the ending index? 0 1 24 25in java Integer numVals is read from input and integer array userCounts is declared with size numVals. Then, numVals integers are read from input and stored into userCounts. Output all elements of userCounts in reverse order, following each element with a space, including the last. After the final output, end with a newline. Ex: If the input is 4 54 56 75 7 then the output is: Array contents in reverse: 7 75 56 54 Note: The loop should start with i = userCounts.length - 1 and end with i = 0. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 import java.util.Scanner; public class UserLog { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intnumVals; inti; numVals=scnr.nextInt(); int[] userCounts=newint[numVals]; for (i=0; i<userCounts.length; ++i) { userCounts[i] =scnr.nextInt(); } System.out.print("Array contents in reverse: "); /* Your code goes here */ } }
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…True or False: Arrays can have new elements added to it without resizingModify the quick sort implementation in the textbook to sort the array using pivot as the median of the first, last, and middle elements of the array. Add the modified quick sort implementation to the arrayListType class provided (arrayListType.h). Ask the user to enter a list of positive integers ending with -999, sort the integers, and display the pivots for each iteration and the sorted array. Main Function #include <iostream>#include "arrayListType.h"using namespace std; int main(){ arrayListType<int> list;int num;cout << "Line 8: Enter numbers ending with -999" << endl;cin >> num; while (num != -999){list.insert(num);cin >> num;} cout << "Line 15: The list before sorting:" << endl;list.print();cout << endl; list.selectionSort();cout << "Line 19: The list after sorting:" << endl;list.print();cout << endl; return 0;} Header File (arrayList.h) Including images #include <iostream>#include <cassert>…
