module Examenler #(parameter P = 4) 日( ); input [P:0] e_a, input [P:0]_e_b, output reg [P+1:0] vs_a always @* begin if (e_a[P] == e_b[P]) begin
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make the test bench(instantiation) and explain how the test bench works (Verilog)
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I wanted them to answer me how to do the bench test of this exercise that I sent :/
- in, java Assume a function g(x) is defined as follows where x is an int parameter:g(x) = g(x - 1) * g (x - 3) if x is even and x > 3 = g(x - 2) if x is odd and x > 3 = x otherwiseWrite a recursive method to compute g.write a python prgram (oop)Implement the design of the Groceries and Buyer classes so that the following code generates the output below: #Write your code herebuyer1 = Buyer('Ross', 'CL23')print('1.===============================')print(buyer1)item1 = Groceries('Mango', 'Fruits')print('2.===============================')print(item1)print('3.===============================')print(Groceries.items)print('4.===============================')Groceries.add_items('Packaged',['Flour 90', 'Noodles 30', 'Soybean-Oil 150'])print(f'Updated Item List:\n{Groceries.items}')print('5.===============================')item2 = Groceries('Flour', 'Packaged', 3)print(item2)print('6.===============================')buyer1.create_bill(item1, item2)print('7.===============================')item3 = Groceries('Orange', 'Fruits', 3)print(item3)print('8.===============================')item4 = Groceries('Rice', 'Packaged', 2)print(item4)print('9.===============================')buyer2 =…Can you translate this to c++ package backtracking;public class RatMazeProblem { final int N = 4; public boolean printMazePath(int[][] maze) { int[][] finalPath = new int[N][N]; if(!printMazePathUtil(maze, 0, 0, finalPath)) { System.out.println("Rat Can't reach to End"); return false; } printPath(finalPath); return true; } private boolean printMazePathUtil(int[][] maze, int x, int y, int[][] sol) { if(x == N - 1 && y == N - 1 && maze[x][y] == 1) { sol[x][y] = 1; return true; } if(isSafe(maze, x, y)) { sol[x][y] = 1; if(printMazePathUtil(maze, x + 1, y, sol)) { return true; } if(printMazePathUtil(maze, x, y + 1, sol)) { return true; } sol[x][y] = 0; } return false; } private boolean isSafe(int[][] maze, int x, int y) { if(x >= 0 && x < N && y >= 0 && y < N && maze[x][y] == 1) {…
- Finish code in Mathematica: The representations of HMMs is also the same. Here's what a call to readHMM[] would look like: hmmObject = readHMMFile["Test/humanMalaria.hmm"]= hmmObject$4958, hmmObject["states"]={"M", "H"} hmmObject["initialStateProbs"]={0.5, 0.5} hmmObject["transitionMatrix"]={{0.5, 0.5}, {0.5, 0.5}} hmmObject["alphabet"]={"A", "C", "G", "T"} hmmObject["emissionMatrix"]={{0.3, 0.25}, {0.2, 0.25}, {0.2, 0.25}, {0.3, 0.25}} observationSeq_ is like: {1, 4, 3, 1, 4, 4, 4, 3, 3, 2, 3, 2, 2, 3, 2} You will have two: buildForwardMatrix and buildBackwardMatrix. You will then combine them inside posteriorProbabilities. posteriorDecode calls posteriorProbabilities and uses the result to find the posterior path and output the corresponding state names. Finish the following four functions in Mathematica: buildForwardMatrix[observationSeq_, hmm_] := Module[{numberOfObservations, numberOfStates, forwardMatrix, observationIndex}, (* Put your code for bulding the forward matrix here.…Computer Science Practice Task : Write a program in phyton language . Implement Water Jug Problem using DFS in Python, initial stage (0,0) and final stage (2,Y). A Water Jug Problem: You are given two jugs, a 4-gallon one and a 3- gallon one, a pump which has unlimited water which you can use to fill the jug, and the ground on which water may be poured. Neither jug has any measuring markings on it. How can you get exactly 2 gallons of water in the 4-gallon jug?error on python code: File "/root/sandbox/MyMotorcycleClassProgram.py", line 11, in <module> motorcycleOne = Motorcycle(90.0)TypeError: Motorcycle.__init__() takes 1 positional argument but 2 were given from Vehicle import Vehicle # Write the Motorcycle class here class Motorcycle(Vehicle): def__init__(self): Vehicle.__init__(self) self._sidecar = sidecar defset_sidecar(self,sC): self._sidecar = sidecar defget_sidecar(self): returnself._sidecar defaccelerate(self,mph): ifself._speed + mph >self._max_speed: self._speed =self._speed + mph else: print("This motorcycle cannot go that fast.")
- Design and implement a simplified voting machine class with the following specification. Avoting machine has a list of candidates and the following methods:i) addCandidate(String name) /* Add a candidate with the name to the list */ii) castVote(String name) /* Cast a vote to the candidate with the name */iii) printResults() /* Print out the number of votes each candidate has received. Theorder does not matter */ Assume that only two attributes of a candidate, namely, the name and number of votes, are ofinterest here, and the size of the candidate list is unknown in advance.Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex: If the input is: PYTHON the output is: 14Go program using method of " Build functions with Reflection to Automate Repetitive Tasks." Output : Calling main.timeMe took 1s Calling main.timeMeToo took 2s 4
- Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex: If the input is: PYTHON the output is: 14 tile_dict = { 'A': 1, 'B': 3, 'C': 3, 'D': 2, 'E': 1, 'F': 4, 'G': 2, 'H': 4, 'I': 1, 'J': 8, 'K': 5, 'L': 1, 'M': 3, 'N': 1, 'O': 1, 'P': 3, 'Q': 10, 'R': 1, 'S': 1, 'T': 1, 'U': 1, 'V': 4, 'W': 4, 'X': 8, 'Y': 4, 'Z': 10 } ''' Type your code here. '''Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, andreturns the largest value and the average in $v0 and $v1 to the calling program. Theprogram must be structured as follows:Subprogram largestAndAverage($a1, $a2, $a3, $a4){ int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3; $s0 = getLarger($a1, $a2); $s0 = getLarger($s0, $a3); $v0 = getLarager(s0, $a4); // Largest is in $v0 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1 return;}Subprogram getLarger($a0, $a1) { $v0 = $a0 if ($a1 > $a0) $v0 = $a1 return;}Note the use of the variables var0...var3. Because the values of $a0 and $a1 (at least) arechanged on the call to getLarger, they will not be available when they are needed to calculatethe average, and must be stored on the stack. To do this problem correctly, you mustcalculate the maximum value using the getLarger subprogram shown here, and it must becalled before the average is calculated. This implies that at a minimum $a0 and $a1 must…Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, andreturns the largest value and the average in $v0 and $v1 to the calling program. Theprogram must be structured as follows:Subprogram largestAndAverage($a1, $a2, $a3, $a4){ int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3; $s0 = getLarger($a1, $a2); $s0 = getLarger($s0, $a3); $v0 = getLarager(s0, $a4); // Largest is in $v0 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1 return;}Subprogram getLarger($a0, $a1) { $v0 = $a0 if ($a1 > $a0) $v0 = $a1 return;}Take note of how var0...var3 are used. The values of $a0 and $a1 (at least) must be placed on the stack because they are not immediately available when needed to calculate the average because they are modified during the call to getLarger. You must use the getLarger subprogram displayed above to calculate the greatest value for this problem, and it must be called before the average calculation. This indicates that at the very least $a0…