Movies (Movie id. Title, Year, Rating, Num_rating) Movie Cast(Movie id. Name, Position_of_cast) Note: Position of the cast is the order of the actor where he/she appears in the list of cast. The query is: CREATE VIEW Number AS SELECT Movie_id FROM Movie_Cast GROUP BY Movie_id HAVING COUNT(*) >= ALL (SELECT COUNT(*) FROM Movie Cast GROUP BY Movie id); SELECT Number.Movie id, title FROM Number, Movies WHERE Number.Movie_id Movies Movie id ORDER BY Movie id;

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Do not run this query. I want only the explanation of “what this query will return.”

Consider the set of relations shown below and the SQL query that follows.
Movies (Movie_id. Title, Year, Rating, Num_rating)
Movie Cast(Movie id. Name, Position_of cast)
Note: Position of the cast is the order of the actor where he/she appears in the list of cast.
The query is:
CREATE VIEW Number
AS
SELECT Movie_id FROM Movie_Cast
GROUP BY Movie_id
HAVING COUNT(*) >= ALL (SELECT COUNT(*)
FROM Movie Cast GROUP BY Movie id);
SELECT Number Movie id, title FROM Number, Movies WHERE Number.Movie_id
Movies Movie id ORDER BY Movie id;
%3D
Transcribed Image Text:Consider the set of relations shown below and the SQL query that follows. Movies (Movie_id. Title, Year, Rating, Num_rating) Movie Cast(Movie id. Name, Position_of cast) Note: Position of the cast is the order of the actor where he/she appears in the list of cast. The query is: CREATE VIEW Number AS SELECT Movie_id FROM Movie_Cast GROUP BY Movie_id HAVING COUNT(*) >= ALL (SELECT COUNT(*) FROM Movie Cast GROUP BY Movie id); SELECT Number Movie id, title FROM Number, Movies WHERE Number.Movie_id Movies Movie id ORDER BY Movie id; %3D
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