mRNA is an intermediate molecule that arises in the decoding of DNA. mRNA is produced by a process called transcription and it eventually decays. Suppose that the rate of transcription is changing exponentially according to the expression ebt and mRNA has a constant per capita decay rate of k. The number of mRNA transcript molecules, T, thus changes as dT = ebt - KT. dt The first term on the right side is time-varying. As a result, the differential equation is not separable. However, the equation can be solved using the change of variables y(t) = bektT(t). Solve the differential equation using this technique. (Let T(0) = To.) T(t) =

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter10: Exponential And Logarithmic Functions
Section10.5: Solve Exponential And Logarithmic Equations
Problem 10.88TI: Researchers recorded that a certain bacteria population declined from 700,000 to 400,000 in 5 hours...
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mRNA is an intermediate molecule that arises in the decoding of DNA. mRNA is produced by a process called transcription and it eventually decays. Suppose that the rate of
transcription is changing exponentially according to the expression ebt and mRNA has a constant per capita decay rate of k. The number of mRNA transcript molecules, T, thus
changes as
dT
dt
=
ebt - KT.
The first term on the right side is time-varying. As a result, the differential equation is not separable. However, the equation can be solved using the change of variables
y(t) = bektT(t). Solve the differential equation using this technique. (Let T(0) = To.)
T(t) =
Transcribed Image Text:mRNA is an intermediate molecule that arises in the decoding of DNA. mRNA is produced by a process called transcription and it eventually decays. Suppose that the rate of transcription is changing exponentially according to the expression ebt and mRNA has a constant per capita decay rate of k. The number of mRNA transcript molecules, T, thus changes as dT dt = ebt - KT. The first term on the right side is time-varying. As a result, the differential equation is not separable. However, the equation can be solved using the change of variables y(t) = bektT(t). Solve the differential equation using this technique. (Let T(0) = To.) T(t) =
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