Multiply: 4x (6x° – 2x? + 3) b. 5x'y'(2x'y – 6x*y³ – 3). a.

Q: D²y+y= tanx

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Q: y+1-2 dy

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Q: Z'1z Where Cil21 ComflexAumber

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Q: Use convolution to solve 4y' + y = cosh 3t, y(0) = 0.

A: The solution is given as

Q: Approximate  ∫21ex^2dx using the Trapazoidal Rule with n=5

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Q: Q.1A) Evaluate 2 (4-x*) 4 cosy dydx 4-y

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Q: What are y(100) and y(101) for y = cosh x?

A: Given that y= cosh x. Compute the derivative. y'=sinhxy"=coshxy3=sinhxy4=coshxyn=sinhx, n is…

Q: dy :- 15x²y and y = 4 when x = -4 dx

A: To solve the initial value problem  dydx = -15 x2ydyy = -15x2 dx

Q: What are y (l00) and y (101) for y = cosh x?

A: Given: y=cosh (x)

Q: Ex. Evaluate the JJex*+2xy+y*) dydx when s tep (x²+2xy+y=) dydx when step Size of X = 0-2 and step…

A: Given: fx,y=x2+2xy+y2 Given step size of (say hx) x=0.5 and(say hy) y=0.5 we need to Evaluate…

Q: Q2: Gives the values of sinhx, coshx ,and find the values of the remaining five hyperbolic…

A: Since, we sinh(x)=43Since, we know that cosh2 (x)-sinh2 (x)=1⇒cosh2 (x)-169=1⇒cosh2 (x)=169+1⇒cosh2…

Q: Complete the graph using the given symmetry property.

A: Consider the given graph,

Q: ren 5x2 + 2xy – y² = 13, find the value of %3D at (3,4). dx2

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Q: · (D² + 3D + 2)y = xsin 2x

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Q: (y* 2xy)dx + 3x²dy = 0 when y(2) = 1 %3D %3D -

A: Given:        (y4-2xy)dx+3x2dy=0        (y4-2xy)dx=-3x2dy          dydx=y4-2xy-3x2…

Q: y = sech 0 (1- In sech 0)

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Q: find all SoluHons) to the equation y+3 = %3D

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Q: (2-x²) y" + 2xy' - 2y = 0 olution to

A: Given differential equation is 2−x2y''+2xy'−2y=0.....1. a We have to verify that y=x is a solution…

Q: Q1) L-1 s(s a) cosht -1 b) 1-cosht c) (cosh2t - 1) d) (1 - cosh2t)

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Q: Value: 11 dy If y=sec (20), find- d0 Enter your answer as an integer or a reducec

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Q: 41 D'(D + 1)y- 3x +4sinx-2 cosx

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Q: If y = (x+1)/(2x - root x' then y' will be?

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Q: dx/dt = square root5 - ex,

A: As per the company rule, we are supposed to solve one problem from a set of multiple problems.…

Q: y = 3Arcsin (2x³) -- Arccos(2x³)

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Q: a. (t-e-4t)² sec²4t -tan 4t]

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Q: Sz sin³ y dy 8. 3 2

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Q: D²y+y=tanx

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Q: y=3x^(3/2) on [2,4] find arclength

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Q: (d) y" + 2y' + y = 8 cosh x.

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Q: Y"-2y'+2y=e^2x(cosx-3sinx) by using  Variation of parameters

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Q: ne complementoru y functon of مو"(3.D( (D+3)'y= Sin3X

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Q: (а) у"— (а + В)y' + аBy %3D 0 (а + B)

A: Answer as follows

Q: dy un 3 sec2 5x, w dr

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Q: 6. (D2 – 6D + 8)y = e2x + sinx %3D

A: The given differential equation is: D2-6D+8y=e2x+sinx   So, the auxiliary equation is: m2-6m+8=0

Q: is Substitute for +4 X = 2tano and dx= 2 Secodo %3D

A: Given integral is ∫x3x2+4dx Substitute for x=2tanθdx=2sec2θdθ

Q: 1- 3tE %3D V. 1 a 4-

A: We have to find a formula for Vf.

Q: . y = 3Arcsin (2x³) -- Arccos(2x³)

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Q: dx 2/3 Thtegrate -27 3)

A: Given: ∫-278dxx23 To determine: The value of given integral. Formula used: ∫xndx=xn+1n+1+C

Q: Solve for y when x is 30 degrees: y=2sinx

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Q: Find y' for 4x + 5y* – 1 = 132 at the point (2, – 1). | At (2, – 1), y' = Preview %3D

A: Given: 4x5+5y4-132 To find: y'  at  (2,-1)

Q: y (t² + 7t + 5) (5t² + 3), tin fir dy

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Q: y = Vx+1,1Sx56

A: The table containing the values of x and y of the function f(x)=x+1 is shown below. x -1 0 1 2 3…

Q: . lim 4y9 + V y--00 /y18 – 1

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Q: 91 182x-x2 9V x²+y² dydx %3D

A: Here we solve double integration problem.

Q: 1. How many cycles would there be in the graph of y = sinx, over the domain Osxs 1080? What about…

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Q: [D3 – 6D2 + 11 D − 6) y = Cosx sinx

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Q: dy 3x - 4 81. if y = %3D dx 12r²

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Q: Find Jog %3D 1-cosx dz n=770

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Q: x² – 4 Find the antiderivative using Trigonometric Substitution. -

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Q: Q4) find the soluation of differention equation using exact equation

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