Multiply cos(x)/csc(x-1) and csc(x+1)/csc(x+1)

Q: f(x) = -3 cos (+)-2

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Q: * Evaluate. [12 [20x cos(5x² - 1)]dx

A: The given integral is   ∫20xcos5x2-1 dx We solve the integral using proper substitution .

Q: Iim tan³x X10 1- Cos2x

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Q: ind f'(x). f(x) = ln(cos5(3x4))

A: topic:- derivatives

Q: Differentiate. g(x)=x°cos x

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Q: Evaluate: [ cos 2x log(1+ tan x) dx

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Q: Graph off (x) = cos2 x - 2 sin x/4.

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Q: Evaluate (3x + cos 4x) dx

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Q: Solve  cos x = 1/5 for x

A: Given,           cosx=15

Q: = Vx* – - 4 cos x+/7x %3D

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Q: cos2x -4 in ax

A: Given,

Q: 1. f(x) = 4x³ · cos x

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Q: 2sin x -1 y = cosx +2

A: Basic identities of trigonometry and differentiation are used

Q: -tanx cscx+2secx cos² 1/2

A: Solution: The objective is to find the value of the given expression

Q: cos2x Evaluate dx sin²2x- 16 12

A: This definite integral is based on the substitution method.

Q: Evaluate ∫cos^2 xdx

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Q: (cscd + Co+0)(1-CosO

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Q: Cos(11°+x)=-sin(2x+6)

A: x

Q: ブーーコニメCos(2x 2.

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Q: y= - 2 cos 4x +3

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Q: Differentiate. f'(x) = f(x) = 8x7-9 cos(x)

A: As per our guidelines we are supposed to answer only one question. Kindly repost other questions as…

Q: 2 cos(2z)- V3 = 0.

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Q: Express the product cos 7x cos x as a sum or difference.

A: The given expression is cos7xcosx

Q: Eliminate arbitrary constant. y=C1 sin 3x + C2 cos 3x + 9x2-2

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Q: f(x csc² 6x - x cos 6x)dx

A: Given: I=∫xcsc26x-xcos6xdx   As we know that; The Sum Rule: ∫fx±gxdx=∫fxdx±∫gxdx And a).…

Q: cos 2xdx CoS Vsin2x

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Q: 2 csc x 1+ cos x 1- cos x

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Q: find cos x if cos 2x=1/9

A: Consider the equation

Q: Evaluate 4x cos(2-3x) dx

A: Given: The objective is to evaluate ∫4xcos2-3xdx.

Q: Integrate x3 cos(x4)

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Q: cos 2x 6. 4

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Q: )- cos-1

A: Given,          cos-132

Q: 3x2 lim x→0 cos(2x) – 1

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Q: esecx+lntanx -dp- 9. cos x

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Q: Evaluate COs 2 4 – x² dx

A: use the property of even function and odd function to evaluate the integral.

Q: cos(x) 2x+3

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Q: Differentiate  cosx/x

A: The given function is f(x) =(cosx)/x       = x-1.cosx

Q: Differentiate. f(x) = 8x5 - 8 cos x f (x) =

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Q: (x)= -5cos(cos(x5)) f'(x)=

A: Follow next step

Q: 6. x" – 16x = cos 2t %3D

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Q: tan xdx cos 2x-7

A: To find the integration.

Q: 8dx 3 cos 2x + 1 -x6

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Q: rsec(x) 3 cos(x)dydx * JO -

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Q: Cos(-) Xdx Sx2

A: Given: 5.∫cos1x5x2dx 6.∫x2-4x2dx

Q: )Evaluatef 4x cos(2-3x) dx

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Q: cos (x2 + 3x +5 ) COS

A: Solved below

Q: |2x cos (x² -5) х cos

A: To find value of ∫2xcosx2-5dx Solution: Let substitute t=x2-5 Differentiating both sides with…

Q: Evaluate cos (4x) dx.

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Q: Solve cos x + cos 3x cos 2x = 0 %3D

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