N) dy x dx X (1+y) y (1-x)

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Homework of differential equation
Q₁: solve the following differential equations
a) xy' y = x² + 2y'
b) (x+y) dx - xdy = 0
<) (X-1)³ dy + 4 (X-1)² Y = X+1
dx
d) cos y dx + (x Siny - cos²y) dy = a
0
X
e) x² Cosy - £ + 2 dx
= 0
dy
f) (y²-4) (x-1) = (x+)) dx
ay
9) y = cosh x + √cosh³x - 1 +7e²
hi 13 XỶ Hy)dx + ( x y + 2x) dyeo
0
I) sin x dy
Sin 2X - Y COS X
dx
k) (1-y²) dx + (1+x²) d y = 0
2) 2x²
dy
=
Csc (X)
dx
My xe x2
=
N) dy X (1+y)
y (1-x)
=
dx
•)(x-1) (X-2) dy + y = X²
Transcribed Image Text:Homework of differential equation Q₁: solve the following differential equations a) xy' y = x² + 2y' b) (x+y) dx - xdy = 0 <) (X-1)³ dy + 4 (X-1)² Y = X+1 dx d) cos y dx + (x Siny - cos²y) dy = a 0 X e) x² Cosy - £ + 2 dx = 0 dy f) (y²-4) (x-1) = (x+)) dx ay 9) y = cosh x + √cosh³x - 1 +7e² hi 13 XỶ Hy)dx + ( x y + 2x) dyeo 0 I) sin x dy Sin 2X - Y COS X dx k) (1-y²) dx + (1+x²) d y = 0 2) 2x² dy = Csc (X) dx My xe x2 = N) dy X (1+y) y (1-x) = dx •)(x-1) (X-2) dy + y = X²
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