n=1 ,2n TO

Q: Write S = n(n-1) n=7 1 as a telescoping series and find its sum. %3D S =

A: Given: S=∑n=7∞ 1n(n-1)

Q: Find the sum of the series if possible, if not possible explain why: 1 ' + 2 + (금) + (금)'+(글) .

A: The given series is: 1+-25+-252+-253+......

Q: Find the sum of the series if possible, if not possible explain why: 3 (금)' + (금) -2 1+ 5 +...

A:

Q: State where the power series is centered. (-1)"(2n – 1) „n Σ * 2"n! n = 1

A: Solving

Q: State where the power series is centered. Ï (-1)^(x – 57)6n (-1)"(х - 5л)бл n = 0 (6n)!

A: Center is 5π .

Q: Find the sum of the series.

A: By using partial fraction, separate out both the factors.

Q: State where the power series is centered. Σ n = 0

A: We have to find center of power series

Q: What is the sum of the series ? 3D1 x+1 O I- 1 O n+ 1

A: Answer is mentioned below

Q: Find the sum of the series: S=∑∞n=0 ((−1)^n)/(4^n)=

A: According to the given information it is required to calculate the sum of the given series:

Q: he sum of the first " n" terms of the series is 2n + 3 + x. Find the seventh term.

A:

Q: Find the sum of the series: S=∑∞n=2 1/(4^n)=

A: Given, series

Q: Find the sum of the series, if it exists. 1 4" 1=9 Select the correct choice. 1 196,608 65,536…

A: To find sum of the series, if it exist ∑n=9∞14n

Q: Find the exact sum of the series if pessible; If not, estimate with S4 and State

A:

Q: Approximate the sum of the series by using the first six terms. n+1 6) n² n=1

A:

Q: 2k – 1 Σ 4k k=1

A:

Q: 2 En=1 n(n+1)

A:

Q: (-1)

A:

Q: The sum of the series is 4k2-1 k=2

A:

Q: What is the sum of the series?

A:

Q: a) ΣΣ п n=0

A:

Q: Find the sums of the series

A: Given that ∑n=1∞(-1)n34n We need to find the sum of the series. By looking at the series it seems to…

Q: Find the Sum of this series:

A:

Q: Find the sum of the series. Σ (-1) 40x8n n! n = 0

A:

Q: State where the power series is centered.

A: Given series: ∑n=1∞-1n2n-12nn!xn This series can be expanded as…

Q: Determine if the series is telescoping: 9. Σ n = 1 nº +3n If the series does telescope, find its…

A:

Q: estimate the sum of the series if n is given as 8

A: Given series∑n=1∞-1n-12n4 We have to calculate the sum for n=8 Now, ∑n=18-1n-12n4=…

Q: 1 Σ 16k? + 8k – 3 k=0

A:

Q: what is the sum of the series? t+1 | 8. t=1 IM:

A: Given series is ∑t=1∞98-52t+1 Here we have to find the sum of series.

Q: State where the power series is centered. Σ 5 (-1)^(x – 57)3n (3n)! n= 0

A: To find the center of power series, set the expression containing 'x'(inside parenthesis) equal to…

Q: Evaluate the series or state that it diverges.

A: Given that : The series ∑k =0∞  116k2 + 8k - 3 . First factoring the denominator term,…

Q: Find the sum of the series S.

A: Given,         3-3ln(2)+3(ln(2))22!-3(ln(2))33!+ . . .

Q: Find the sum of the series below. 56n n=1 (2n – 1) (2n + 1)? The sum of the series is

A:

Q: State where the power series is centered. 00 (-1)"(x – 5x)8n Σ n = 0 (8n)!

A:

Q: Find the sum of the series, S. n! S =

A: We need to evaluate the sum of the following series : ∑n=0∞x8nn!

Q: State where the power series is centered. Σ (−1)"(x – 7π)5η (5η)! n = 0

A:

Q: Find the sum of the series and put the result in simplest form.

A:

Q: State where the power series is centered. Σ Š (-1)"(x – 6x) 5n | n = 0 (5n)!

A: We use definition of centered of power series.

Q: Find the sum of n terms of the series whose nth term is (i) 2n? - 3n + 5 (ii)n? + 2"

A:

Q: How many terms of the series (-1)" 1 + 2" n=1 are needed to compute the sum of the series with an…

A: To find the number of term such that the error is less than 0.001 .

Q: п (х-2)" b) Σ 3 п n=1

A: Given that ∑n=1∞x-2nn3we have to find centered of power series

Q: State where the power series is centered. (-1)"(9n – 1) 9 n! n= 1

A:

Q: 4K-1 K=4

A: To find the sum of the series.

Q: Evaluate the series or state that it diverges.

A:

Q: State where the power series is centered. ř (-1)"(x - 3)6n (6n)! n= 0

A:

Q: Find the sum of each series

A:

Q: State where the power series is centered. Σ nx" n= 0

A: A power series centred at (or about) x=c is a series of terms such that all terms are non-negative…

Q: State where the power series is centered. Σ (-1)"(x – 6x)ªn (4n)! n - 0

A:

Q: Find the sum of the series Σ /n+4 n = 1

A: First operate the given sum on both terms and then calculate the sum.