Question
Asked Oct 28, 2019
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Determine if the series below converges or diverges. Show all steps in whichever test you use. If a test is specified, you must use that test. Otherwise you are restricted to the direct comparison and limit comparison. 

n+1
Σ
d.
4n2+3
n=1
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n+1 Σ d. 4n2+3 n=1

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Expert Answer

Step 1
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Vn1 The given series is Th 4n2+3 Apply Limit comparison test: If lim Cwhere 0 <c <o, then a, and b either both converges or diverges 0, ifb converges, then a, converges when lim ifb diverges, then a, converges when lim 2 2

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Step 2
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Define b as follows: Vn+1 like let b Since 2 4n2+3 Vn+1 1 and b Take an 4m+3 2 Find the value of lim, b 2

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Math

Calculus

Limits

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