n3 + 6n an 4n + n4 lim an II

Q: Dividing numerator and denominator by n², we have 6 + 15m² lim n- n + 12n² = lim 6 + 15m² n² n+ 12n²…

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Q: V5 n +9 lim . Show your work. 9 n+5 n- 00

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Q: lim2

A: Explained below

Q: れ ポ+n3 lim (nj)2 + n4 j=1 n-00

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Q: „i 4+! -2 29. lim n00

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Q: lim 4 į (( #)² + ¹); n n

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Q: Ve 3n 2n an Find lim an n

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Q: 252+8 6. lim r+2

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Q: Lim a 2.

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Q: 23. lim 1 /n² +1

A: To prove: limn→∞nn2+1=1

Q: 71. lim = 0 n+00

A: Given: limn→∞1n4+n8=0 we have to prove this for this we solving L.H.S taking n8  common

Q: 6. lim (0.2)

A: As per bartleby guidelines we only give first question answers.

Q: lim 6+ -3

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Q: n (n + 2\ 3. lim 2n

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Q: > 11. lim 2'/n² = 1 n00

A: Given: prove that limn→∞21n2=1 we know that when, n→∞, 1n2→0

Q: Evaluate the limit.

A: limx→∞ t4/3 - 9t1/38t4 + 21/3 = ?

Q: - 1 32. lim 12-12 +3) ² +3. A 1 -1 D -4

A: We will solve this limit equation using L'hospital method.

Q: n=1 m sup,+∞ an = (lim infn an)+2. %3D n-00

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Q: lim (Vn? + 4n –- n) = n-00 Select one: O 1 O 2 2 none

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Q: lim n2 + 1 n2 + n2 n2 + 4

A: The given limit is: limn→∞nn2+1+nn2+4+...+nn2+n2 so, it can be written as: limn→∞ ∑r=1nnn2+r2

Q: n+: n+5 15. lim tan- n-00

A: Given- limn→∞tan-1n+2n+5=π4 To prove- The above integral.

Q: Find the limit.

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Q: 32. lim r-2-2 + 3 A 1 B -1 D -4

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Q: Inª -3n+1 lim In-3n+1 5n+4n+5 n-+00

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Q: 2х lim х2 — 9 ||

A: To evaluate: limx→02xx2-9 We know that if a is in the domain of f(x), then limx→af(x) = f(a)

Q: 1. lim n2+5".

A: As per our guidelines we are supposed to answer only one question. Kindly repost others question as…

Q: lim( 2n') %3D

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Q: n lim Σ 3 1+

A: Integration: n→∞lim∑i=1∞ 1+7in3 (7n)Here △x=7nci=a+i△x   =1+i7n   =1+7inTherefore f(x)=x3and here…

Q: 1 lim 1 +...+ 22 1 2n +

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Q: 1 1 3. lim ed - 1

A: Given query is to find the limit of the expression.

Q: 9n+100 lim n+2

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Q: lim e5x — 2e-2х + е-3х + 2е-5х —5е-10х n→0∞ 2х-4

A: Topic:- limits

Q: х3 - 5х + 2 lim 2х3 -7 А. О В. 1 С. D. 7 II

A: To evaluate limx→∞x3-5x+22x3-7

Q: k) lim(23+10¯"

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Q: Lim 3 128 2 J

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Q: 6n +3n = 3 2n² -5 (c) lim

A: we know,         lim(1/n) =0 if n is tend to infinity

Q: nt P(1+ lim

A: Simple calculation of limit by using log

Q: 3. lim X→n/2

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Q: z3+1 lim z-1 z2+1 .A .B -2 3 .C 2 3 OMIN

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Q: n'-3n+1 3n+2n+5 lim

A: The value of the given limit is 1/3

Q: (2a² +3a +11) a-5 lim a2 +3a-7 In a 00 a+10

A: Solution is here

Q: 2+ 31 + 2 2-1-2 24.) lim

A: To find The limit of the above

Q: x'- 81 Lim メー3 メー3

A: Wé have to find limit

Q: (2+ )". 1/3 = 2!/3 53. lim n00

A: Given that limn→∞ 2+4n213=213. Prove this limit as follows.

Q: n+3 E) Lim (- 3n

A: The value of limn→∞1-13nn+3 can be calculated as, limn→∞1-13nn+3=1-1∞∞…

Q: 5. lim(√n²+ n − n). -

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Q: 6n2 6n2+8 lim tan

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