Name:-11. The graph of the function y=x2-6x+ 8 is:12 XFind the coordinates of its vertex and its intercepts.vertex (-3, 1); x-intercepts-2, 4; y-intercept 7b.a.vertex (3,-1); x-intercepts 8; y-intercept 2, 4vertex (4, 2); x-intercepts 8, 7; y-intercept 2d.arec.vertex (3, -1); x-intercepts 2, 4; y-intercept 8vertex (6,-2); x-intercepts 3, 6; y-intercept 6For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh.e.12.%3D%3D(fog•h)(x) = (~F - 10) +3(fogoh)(x) = x' +x-7+ /xgogoh)(x) = (~x -7)'a.b.%3DC.d. (fogoh)(x) = /x -7e. fogoh)(x) = (x' +3)+ (x – 10)~/x%3D%3D

Question
Asked Dec 10, 2019
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Name:
-11. The graph of the function y=x2-6x+ 8 is:
12 X
Find the coordinates of its vertex and its intercepts.
vertex (-3, 1); x-intercepts-2, 4; y-intercept 7
b.
a.
vertex (3,-1); x-intercepts 8; y-intercept 2, 4
vertex (4, 2); x-intercepts 8, 7; y-intercept 2
d.
are
c.
vertex (3, -1); x-intercepts 2, 4; y-intercept 8
vertex (6,-2); x-intercepts 3, 6; y-intercept 6
For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh.
e.
12.
%3D
%3D
(fog•h)(x) = (~F - 10) +3
(fogoh)(x) = x' +x-7+ /x
gogoh)(x) = (~x -7)'
a.
b.
%3D
C.
d. (fogoh)(x) = /x -7
e. fogoh)(x) = (x' +3)+ (x – 10)~/x
%3D
%3D
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Name: -11. The graph of the function y=x2-6x+ 8 is: 12 X Find the coordinates of its vertex and its intercepts. vertex (-3, 1); x-intercepts-2, 4; y-intercept 7 b. a. vertex (3,-1); x-intercepts 8; y-intercept 2, 4 vertex (4, 2); x-intercepts 8, 7; y-intercept 2 d. are c. vertex (3, -1); x-intercepts 2, 4; y-intercept 8 vertex (6,-2); x-intercepts 3, 6; y-intercept 6 For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh. e. 12. %3D %3D (fog•h)(x) = (~F - 10) +3 (fogoh)(x) = x' +x-7+ /x gogoh)(x) = (~x -7)' a. b. %3D C. d. (fogoh)(x) = /x -7 e. fogoh)(x) = (x' +3)+ (x – 10)~/x %3D %3D

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Expert Answer

Step 1

Option (d) is the correct option.

Consider the given function and the general equation form for the quadratic equation.

Compare the given function and the general equation form for the quadratic equation and find a, b and c.

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y = ax + bx +c ..(1) y = (1).x² – 6x +8 y =x - 6x+8 Therefore, a=1 b =-6

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Step 2

Then, find the value of x-coordinate of the vertex by the formula, Xv = -b/2a.

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Xv = 2a (-6) 2(1) = 3 ||

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Step 3

Now, find the value of y-coordinate of the vertex by putting the valu...

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y = x² - 6x +8 .(1) Yy = X - 6Xv +8 = (3)' – 6(3)+8 = 9-18+8 = -1 Therefore, (Xv, Yv)=(3,-1)

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Calculus