# Name:-11. The graph of the function y=x2-6x+ 8 is:12 XFind the coordinates of its vertex and its intercepts.vertex (-3, 1); x-intercepts-2, 4; y-intercept 7b.a.vertex (3,-1); x-intercepts 8; y-intercept 2, 4vertex (4, 2); x-intercepts 8, 7; y-intercept 2d.arec.vertex (3, -1); x-intercepts 2, 4; y-intercept 8vertex (6,-2); x-intercepts 3, 6; y-intercept 6For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh.e.12.%3D%3D(fog•h)(x) = (~F - 10) +3(fogoh)(x) = x' +x-7+ /xgogoh)(x) = (~x -7)'a.b.%3DC.d. (fogoh)(x) = /x -7e. fogoh)(x) = (x' +3)+ (x – 10)~/x%3D%3D

Question
4 views help_outlineImage TranscriptioncloseName: -11. The graph of the function y=x2-6x+ 8 is: 12 X Find the coordinates of its vertex and its intercepts. vertex (-3, 1); x-intercepts-2, 4; y-intercept 7 b. a. vertex (3,-1); x-intercepts 8; y-intercept 2, 4 vertex (4, 2); x-intercepts 8, 7; y-intercept 2 d. are c. vertex (3, -1); x-intercepts 2, 4; y-intercept 8 vertex (6,-2); x-intercepts 3, 6; y-intercept 6 For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh. e. 12. %3D %3D (fog•h)(x) = (~F - 10) +3 (fogoh)(x) = x' +x-7+ /x gogoh)(x) = (~x -7)' a. b. %3D C. d. (fogoh)(x) = /x -7 e. fogoh)(x) = (x' +3)+ (x – 10)~/x %3D %3D fullscreen
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Step 1

Option (d) is the correct option.

Consider the given function and the general equation form for the quadratic equation.

Compare the given function and the general equation form for the quadratic equation and find a, b and c. help_outlineImage Transcriptionclosey = ax + bx +c ..(1) y = (1).x² – 6x +8 y =x - 6x+8 Therefore, a=1 b =-6 fullscreen
Step 2

Then, find the value of x-coordinate of the vertex by the formula, Xv = -b/2a.

Step 3

Now, find the value of y-coordinate of the vertex by putting the valu... help_outlineImage Transcriptionclosey = x² - 6x +8 .(1) Yy = X - 6Xv +8 = (3)' – 6(3)+8 = 9-18+8 = -1 Therefore, (Xv, Yv)=(3,-1) fullscreen

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### Calculus 