I need just the answer of (e)(i) Draw the flow curve and obtain the liquid limit(ii) What is the plasticity index of the soil?(iii) Determine the liquidity index of the soil if the natural water content is 29.5%. The following are the results of a sieve analysis test are presentaed in Table Q1.Table Q1|US Sieve NO. | Opening (mm) | Mass of soil retained (g)44.7563.3530.0102.0048.7200.850127.3400.42596.8600.25076.61000.15055.22000.07543.4pan22.0(a) From the above table,Compute the values of percentage retained; cumulative percentage retained; and(i)percentage finer for each of the given sieve sizes.(ii) Plot a grain-size particle distribution curve.(b) From your curve, obtain the values of:(i) Dio ; D30 ; D(ii) Coefficient of uniformity, C.(iii) Coefficient of curvature, C.(c)Determine the percentage of the following types of soil in the sample;(i) Gravel(ii) Coarse -grained sand(iii) Medium grained sand(iv) Fine grained sand(v) Fines (silt + clay)The following data were recorded during a shrinkage limit test on the sample from the soil:• Initial volume of soil in a saturated state = 20.6 cm• Final volume of soil in a dry state = 13.8 cm• Initial mass in a saturated state = 47.5 gFinal mass in a dry state = 34.6 g(d)(i) Determine the shrinkage limit of the soil sample.(ii) Determine the shrinkage ratio.lilitary Technological College - OmanPage | 1A liquid limit test, conducted on the soil sample in the Casagrande cup device, gave thefollowing results:Number of blows, N Moisture content (%)52.51247.1(e)2043.22838.63237.0Two determinations for the plastic limit gave water contents of 22.8% and 23.2% for the firstand second trial respectively.(i) Draw the flow curve and obtain the liquid limit(ii)What is the plasticity index of the soil?(iii) Determine the liquidity index of the soil if the natural water content is 29.5%. A liquid limit test, conducted on the soil sample in the Casagrande cup device, gave thefollowing results:Number of blows, N | Moisture content (%)52.561247.1(e)2043.238.637.02832Two determinations for the plastic limit gave water contents of 22.8% and 23.2% for the firstand second trial respectively.(i) Draw the flow curve and obtain the liquid limit(ii) What is the plasticity index of the soil?(iii) Determine the liquidity index of the soil if the natural water content is 29.5%.

Answered: Image /qna-images/answer/6c5f4458-da84-4be2-8686-3a3bd88fa66b.jpg

need just the answer of (e) (i) Draw the flow curve and obtain the liquid limit (ii) What is the plasticity index of the soil? (iii) Determine the liquidity index of the soil if the natural water content is 29.5%.

need just the answer of (e) (i) Draw the flow curve and obtain the liquid limit (ii) What is the plasticity index of the soil? (iii) Determine the liquidity index of the soil if the natural water content is 29.5%.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL=25 and the in situ moisture content is 45%. Determine the liquid limit. O a. 41 O b. 47 O c. 43 O d. 50
A permeameter of 8.2cm diameter contains a sample of soil of lemgth 35cm. It can be used either for constant head or falling head tests. The standpipe used for the latter has a diameter of 2.5cm. In the constant head test the loss of head was 116cm measured on a length of 25cm when the rate of flow was 2.73ml/s. If a falling head test were then made on the same soil, how kuch time in seconds would be taken for the head to fall from 150 to 100cm?
The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 25 and the in situ moisture content is 50%. Determine the liquidity index. a.0.91 b.1.25 c.0.56 d.0.59 With FBD if necessary
The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 25 and the in situ moisture content is 45%. Determine the liquid limit. a.41 b.43 c.50 d.47
A falling-head permeability test was performedin a permeameter with an inside diam. of 6 cm.The inside diameter of the standpipe is 3 mm.The sample had a length of 12 cm. During aperiod of 8 min. the head of the sample was120 cm and decreased by 50 cm. Computethe coefficient of permeability of the samplein cm/sec.
) A pumping test carried out in a 50 m thick confined aquifer resulted in a flow rate of 600l/min. The thickness of the impermeable layer above the aquifer is 20 m and the originalwater level in the well was 2 mm below the ground surface (which is also the top of theimpermeable layer). Drawdowns in two observation wells located 50 m and 100 m fromthe well are 3 and 1 m respectively. Calculate:i) The coefficient of permeability of the aquifer, ii) The drawdown in the well, iii) The radius of influence. The diameter of the well is 0.6 m.
The discharge of water collected from a constant head permeameter in a period of 15 minutes is 500 ml. The internal diameter of the permeameter is 5 cm and the measured difference in head between two gauging points 15 cm vertically apart is 40 cm. Calculate (a) the coefficient of permeability (mm/s), (b) If the dry weight of the 15-cm long sample is 4.86 N and the specific gravity of the solids is 2.65, calculate the seepage velocity (mm/s).
8. The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 25 and the in situ moisture content is 45%. Determine the liquid limit. a.43 b.50 c. 47 d.41
49. A pumping test was made in a sand layer extending to a depth of 16m. The initial groundwater table was located 2m below the ground surface. Observation wells were sighted at distances 4m and 9.5m from the pumping well. Using a discharge of 0.4 cubic meters per hour, a steady level is attained at the pumping well. The measured drawdowns at the two observation wells are 2m and 0.25m respectively. Determine the coefficient of permeability of the soil.
In a constant head permeameter test, the length of the specimen is 200 mm and the cross-sectionalarea is 78.5 cm2. If k = 2.1 x 10-2cm/sec, and a rate of flow of 130 cm3/min must be maintainedduring the test, what should be the head difference across the specimen?
2. The following description is correct ( ).A. the denser the grid in the flow network, the smaller the hydraulic gradientB. two points on the same equipotential line, the pore water pressure is always the sameC. the same flow network, any two adjacent equipotential line between the potential energy difference is equalD. The direction of the infiltration flow rate is the direction normal to the flow line 3. In the triaxial shear test, the test that keeps the pore pressure of the soil sample at zero throughout the process from the application of the circumferential pressure until the soil sample is damaged is ( ).A. Unconsolidated undrained test B. Consolidated drained testC. Solidification without drainage test D. Solidification fast shear test
The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 25 and the in situ moisture content is 45%. Determine the liquidity index. a. 0.56 b. 0.91 c. 1.25 d. 0.59