Network Address: 192.70.10.0 Number of needed hosts: 8 Default subnet mask: New subnet mask: Number of subnets created: Number of hosts per subnet: First usable address of the first subnet: Last usable address of the first subnet: Broadcast address of the first subnet:

Network Address: 192.70.10.0 Number of needed hosts: 8 Default subnet mask: New subnet mask: Number of subnets created: Number of hosts per subnet: First usable address of the first subnet: Last usable address of the first subnet: Broadcast address of the first subnet:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Network Address: 192.70.10.0
Number of needed hosts: 8
Default subnet mask:
New subnet mask:
Number of subnets created:
Number of hosts per subnet:
First usable address of the first subnet:
Last usable address of the first subnet:
Broadcast address of the first subnet:
First usable address of the third subnet:
Last usable address of the third subnet:
Broadcast address of the third subnet:

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Given each IP address and mask, supply the following information for each of these 9 examples: a) Size of the network part of the address (No. of network bits). b) Size of the subnet part of the address (No. of subnet bits). c) Size of the host part of the address (No. host bits). d) The number of hosts per subnet e) The number of subnets in this network f) The subnet address g) First address h) The broadcast address 1. 10.180.10.18, mask 255.192.0.0 2. 10.200.10.18, mask 255.224.0.0 3. 172.31.100.100, mask 255.255.224.0 4. 172.31.200.10, mask 255.255.248.0 5. 192.168.100.100, mask 255.255.255.240 6. 192.168.100.100, mask 255.255.255.248 7. 192.168.15.230, mask 255.255.255.252 A-h has been solved Kindly solve 1-7
1.1 Consider the given IP address and subnet mask, write using CIDR notation. IP address: 192.168.1.0 & subnet mask: 255.255.255.0 [2] IP address: 10.0.0.0 & subnet mask: 255.255.255.128 [2] IP address: 172.16.00 & subnet mask: 255.255.0.0 [2]