Next we substitute 'x s(x) = √² f* VI √ 1 + (f'(t))² dt 4 = dy dx - [~ √₂ + ( ₁6(+) = 1 3x J = 3x¹/2 1 + into the equation for the arc length function and simplify. X t dt 2 +²/2) ² dt
Next we substitute 'x s(x) = √² f* VI √ 1 + (f'(t))² dt 4 = dy dx - [~ √₂ + ( ₁6(+) = 1 3x J = 3x¹/2 1 + into the equation for the arc length function and simplify. X t dt 2 +²/2) ² dt
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.4: Definition Of The Derivative
Problem 6YT
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![Next we substitute
dy
dx
= 3x¹/2
X
5(x) = f*
= √ 1 + (f'(t))² dt
J4
X
= 6₁₁ √√₂+
S
1
- (² √ ₁ + ( 3x (+)
1
into the equation for the arc length function and simplify.
* t¹/
(¹/2)² at
dt
t dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4971f23-5570-4fed-8cd6-5e1a07d18a42%2F5ebea96d-10d2-4c6c-bb5e-b54c9fdf8587%2Fwlzf9t_processed.png&w=3840&q=75)
Transcribed Image Text:Next we substitute
dy
dx
= 3x¹/2
X
5(x) = f*
= √ 1 + (f'(t))² dt
J4
X
= 6₁₁ √√₂+
S
1
- (² √ ₁ + ( 3x (+)
1
into the equation for the arc length function and simplify.
* t¹/
(¹/2)² at
dt
t dt
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