To find the length of one turn of the helix given by r(t) = b (cos) ti + b(sin)j + sqrt(1-b^2) k, t should go from (blank) to (blank) 0 to pi, 0 to 2pi, 0 to 1, or 0 to 2? Now find the length of one turn of the given helix, is it 1, 4pi, pi, or 2pi?
To find the length of one turn of the helix given by r(t) = b (cos) ti + b(sin)j + sqrt(1-b^2) k, t should go from (blank) to (blank) 0 to pi, 0 to 2pi, 0 to 1, or 0 to 2? Now find the length of one turn of the given helix, is it 1, 4pi, pi, or 2pi?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 102E
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To find the length of one turn of the helix given by r(t) = b (cos) ti + b(sin)j + sqrt(1-b^2) k, t should go from (blank) to (blank)
0 to pi, 0 to 2pi, 0 to 1, or 0 to 2?
Now find the length of one turn of the given helix, is it 1, 4pi, pi, or 2pi?
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No sorry it wasn't meant to be done for each individual one, it's one option for the listed ones provided. So only one answer for (blank to (blank I think it's 0 to 2pi but I wasn't sure and one length that I think is 1
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