NOTE: Parts A and Part B are already included. I need help with Part C. That is why I included Parts A and B.

icon
Related questions
Question

NOTE: Parts A and Part B are already included. I need help with Part C. That is why I included Parts A and B.

Part C
Find an equation for the second derivative of 3 coordinate.
Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, B.
15. ΑΣΦ
d²x3 = 2x3
dt²
Submit Previous Answers Request Answer
X Incorrect; Try Again; 5 attempts remaining
?
The main task is to find three new variables whose differential equation is the SHM equation, meaning that they oscillate at a single
frequency that you can identify. The first is w = x₁ + (mc/mo)x2 + x3. Notice that the mc/mo=a²/8². If you calculate
d²w/dt², you'll find that it equals zero. (Check this to verify that your work is correct to this point.) This seems odd, but notice that
multiplying w by mo gives an expression for the center of mass. So what you've learned is that the center of mass doesn't accelerate.
It could be drifting through space, but for this problem you can let the center of mass be at rest at the origin. So the solution to
d² w/dt² = 0 is w = 0.
Transcribed Image Text:Part C Find an equation for the second derivative of 3 coordinate. Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, B. 15. ΑΣΦ d²x3 = 2x3 dt² Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining ? The main task is to find three new variables whose differential equation is the SHM equation, meaning that they oscillate at a single frequency that you can identify. The first is w = x₁ + (mc/mo)x2 + x3. Notice that the mc/mo=a²/8². If you calculate d²w/dt², you'll find that it equals zero. (Check this to verify that your work is correct to this point.) This seems odd, but notice that multiplying w by mo gives an expression for the center of mass. So what you've learned is that the center of mass doesn't accelerate. It could be drifting through space, but for this problem you can let the center of mass be at rest at the origin. So the solution to d² w/dt² = 0 is w = 0.
The greenhouse-gas carbon dioxide molecule CO2
strongly absorbs infrared radiation when its vibrational
normal modes are excited by light at the normal-mode
frequencies. CO₂ is a linear triatomic molecule, as
shown in (Figure 1), with oxygen atoms of mass mo
bonded to a central carbon atom of mass mc. You
know from chemistry that the atomic masses of carbon
and oxygen are, respectively, 12 and 16. Assume that
the bond is an ideal spring with spring constant k.
There are two normal modes of this system for which
oscillations take place along the axis. (You can ignore
additional bending modes.) In this problem, you will find
the normal modes and then use experimental data to
determine the bond spring constant.
Figure
mo
k
2
mc
1x₂
k
<
1 of 1 >
3
mo
X3
Part A
Let x₁, x2, and 3 be the atoms' positions measured from their equilibrium positions. First, use Hooke's law to write the net force
on each atom. Pay close attention to signs! For each oxygen, the net force equals mod²x/dt². Carbon has a different mass, so its
net force is mcd²x/dt². Define a² = k/mo and ß² = k/mc. Find an equation for the second derivative of ₁ coordinate.
Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, ß.
d²x₁
dt²
Submit Previous Answers
= -a²x₁ + a²x₂
✓ Correct
Part B
Find an equation for the second derivative of 2 coordinate.
Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, B.
d²x2
dt²
=
Submit
-23²x₂ + ß²x₁ + ²x3
Previous Answers
Review
Correct
Transcribed Image Text:The greenhouse-gas carbon dioxide molecule CO2 strongly absorbs infrared radiation when its vibrational normal modes are excited by light at the normal-mode frequencies. CO₂ is a linear triatomic molecule, as shown in (Figure 1), with oxygen atoms of mass mo bonded to a central carbon atom of mass mc. You know from chemistry that the atomic masses of carbon and oxygen are, respectively, 12 and 16. Assume that the bond is an ideal spring with spring constant k. There are two normal modes of this system for which oscillations take place along the axis. (You can ignore additional bending modes.) In this problem, you will find the normal modes and then use experimental data to determine the bond spring constant. Figure mo k 2 mc 1x₂ k < 1 of 1 > 3 mo X3 Part A Let x₁, x2, and 3 be the atoms' positions measured from their equilibrium positions. First, use Hooke's law to write the net force on each atom. Pay close attention to signs! For each oxygen, the net force equals mod²x/dt². Carbon has a different mass, so its net force is mcd²x/dt². Define a² = k/mo and ß² = k/mc. Find an equation for the second derivative of ₁ coordinate. Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, ß. d²x₁ dt² Submit Previous Answers = -a²x₁ + a²x₂ ✓ Correct Part B Find an equation for the second derivative of 2 coordinate. Express your answer in terms of some, all, or none of the variables ₁, 2, 3, and the constants a, B. d²x2 dt² = Submit -23²x₂ + ß²x₁ + ²x3 Previous Answers Review Correct
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer