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Note: You should leave any answers in surd form, instead of using decimals. To input inverse trig functions use asin() instead of arcsin, for sin 0. Similarly for the cosine and tangent functions. You can input square roots eg. 5 as sqrt(5). Calculate by using integration by substitution, 5 x dx Į xt +3 What was your substitution? u = What was your new integral in terms of u? In particular if the new integral was of the form A g(u)du where A E R then A = g(u) =

Note: You should leave any answers in surd form, instead of using decimals. To input inverse trig functions use asin() instead of arcsin, for sin 0. Similarly for the cosine and tangent functions. You can input square roots eg. 5 as sqrt(5). Calculate by using integration by substitution, 5 x dx Į xt +3 What was your substitution? u = What was your new integral in terms of u? In particular if the new integral was of the form A g(u)du where A E R then A = g(u) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Note: You should leave any answers in surd form, instead of using decimals. To input inverse trig functions use asin () instead of arcsin, for sin-'0. Similarly for the cosine and tangent functions. You can input square roots eg. V5 as sqrt(5). Calculate by using integration by substitution, 5· x dx x4 + 3 What was your substitution? What was your new integral in terms of u? In particular if the new integral was of the form A g(u)du where A E R then A = g(u) = %3D
Transcribed Image Text:Note: You should leave any answers in surd form, instead of using decimals. To input inverse trig functions use asin () instead of arcsin, for sin-'0. Similarly for the cosine and tangent functions. You can input square roots eg. V5 as sqrt(5). Calculate by using integration by substitution, 5· x dx x4 + 3 What was your substitution? What was your new integral in terms of u? In particular if the new integral was of the form A g(u)du where A E R then A = g(u) = %3D
Finally calculate this integral. Your answer should be of the form B·h(x) + C where BERand C is the constant of integration. What is B = h(x) = Hence, or otherwise, calculate, /2 Злх dx -v2 4 + x4 Ans =
Transcribed Image Text:Finally calculate this integral. Your answer should be of the form B·h(x) + C where BERand C is the constant of integration. What is B = h(x) = Hence, or otherwise, calculate, /2 Злх dx -v2 4 + x4 Ans =
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