Now we can finish determining det(A – A1). (Hint: To factor the cubic expression in the last step, notice by inspection in the second line that 1 = -1 is a root and use the Rational Roots Theorem.) |1- 2 2 -1 - A = (1 - 2)det(A,1) - (0)det(A12) + (2)det(A13) 1 - 2 3 3 %3D = (1 - 1)((-1)((1 + A)(1 - 1))) + 0 + 2((2)(1 + 2)) -(1 - 1)(1 - 2) + (1 + 1) = -23 + 22 +( + 3 -(a - 3)(2 + = To conclude, state the characteristic polynomial of A.
Now we can finish determining det(A – A1). (Hint: To factor the cubic expression in the last step, notice by inspection in the second line that 1 = -1 is a root and use the Rational Roots Theorem.) |1- 2 2 -1 - A = (1 - 2)det(A,1) - (0)det(A12) + (2)det(A13) 1 - 2 3 3 %3D = (1 - 1)((-1)((1 + A)(1 - 1))) + 0 + 2((2)(1 + 2)) -(1 - 1)(1 - 2) + (1 + 1) = -23 + 22 +( + 3 -(a - 3)(2 + = To conclude, state the characteristic polynomial of A.
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 3EQ: In Exercises 1-12, compute (a) the characteristic polynomial of A, (b) the eigenvalues of A, (c) a...
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