Now, we use the Power Rule for Integration, 1 xa dx = xa a + 1 + C₁ a +1 to find the antiderivative: "25 25 √ √ ²³ x-1/2 dx = [ 19 25 19 9.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please help. The answer is not 4. 

Now, we use the Power Rule for Integration,
1
xa dx =
xa
a + 1
+ C₁
a +1
to find the antiderivative:
"25
25
√ √ ²³ x-1/2 dx = [
19
25
19
9.
Transcribed Image Text:Now, we use the Power Rule for Integration, 1 xa dx = xa a + 1 + C₁ a +1 to find the antiderivative: "25 25 √ √ ²³ x-1/2 dx = [ 19 25 19 9.
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