In Problems 29–34, write the equation and graph the linethat passes through the given point and has the slopeindicated.29. (2, 0) with slope -531. (1,4) with slope -33. (-1, 1) with undefined slope34. (1, 1) with 0 slope30. (1, 1) with slope32. (3, – 1) with slope 1In Problems 35-38, write the equation of each linepassing through the given pair of points.35. (3, 2) and (-1, -6)37. (7, 3) and (-6, 2)36. (-4, 2) and (2, 4)38. (10, 2) and (8, 7)

Topic:- Geometry Note:- as per our guideline if more three subparts posted than only first three…

Answered: ns 29–34, write the equation and graph…

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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In Problems 7 & 8, Find an equation in point-slope form, y-y1=m(x-x1), of the line through the given points. 7. (2,7) and (4, -5) 8. (3, 20) and (-5,4) Can Explain to me Step by Step
Find the y-intercept of a line passing through point (2,0) and with a slope of m= -5/4
If line k has the same slope as the graph 4y - x = 2, and (1, 2) is a point on line k, what is the equation of line k?
Find the equation of the line perpendicular to the liney = 2x + 1 and containing the point (3, 5). Express youranswer in slope–intercept form and graph the line.
Find the equation of the line perpendicular to the liney = 2x + 1 and containing the point (3, 5). Express youranswer in slope–intercept form and graph both lines.
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In Problems 1–3, use P1 = (- 1, 3) and P2 = (5, - 1).1. Find the distance from P1 to P2.2. Find the midpoint of the line segment joining P1 and P2.3. (a) Find the slope of the line containing P1 and P2.(b) Interpret this slope
So the solution to this problem was supposed to be -3: "Since the slope of the line is 4, we know that the rise over run is 4/1. Therefore, for every increase of 1 in x, there is an increase of 4 in y. Starting from (-3, 5), we can move 2 units to the left and 8 units down to get to the x-axis. Therefore, the y-coordinate of the point where the line intersects the x-axis is 5 – 8 = -3." I don't see how they got -3 and not 0...what am I not understanding? p.s. this is a "hard" GRE quantitative reasoning ques
If the relationship between y and x is given by the equation y = 1.57 − 0.0407 x, the slope coefficient 0.0407 means this: __________. for every unit increase in x, y decreases by 0.0407 for every unit increase in x, y increases by 0.0407 for every unit increase in x, y increases by 1.5293 for every unit increase in x, y decreases by 1.5293

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ns 29–34, write the equation and graph the line that passes through the given point and has the slope indicated. 29. (2, 0) with slope -5 31. (-1, 4) with slope 30. (1, 1) with slope 32. (3, -1) with slope 1 | 33 (-1 1) with undofinnd