nsiderations. 2. Define a system and perform an energy balance to obtain an expression for the amount of work that can be produced from one mole of gas flowing through the turbine. Please explain all n

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1. Draw a schematic of the process with annotations indicating the relevant inlet/outlet along with heat/work considerations.

2. Define a system and perform an energy balance to obtain an expression for the amount of work that can be produced from one mole of gas flowing through the turbine. Please explain all necessary/relevant approximations/assumptions.

3. Determine a numerical value for the amount of work produced by the turbine per mole of gas.

4. Determine the change in entropy of the universe for the process (per one mole of gas flowing through the turbine).

A common way to extract work from changes in thermodynamic state is by flowing a gas through a turbine.
initially at 100 bar and 600 K flowing rapidly through a turbine end exiting at
Consider a real gas that
18 bar and 450 K.
The following information is available.
• The ideal-gas, constant-pressure heat capacity is cG/R = 3.6 +0.0024T [K]
ap²
T
• The data for PuT is well represented by P(v − b) = RT +
● In the above, a = 0.001 (m³K)/(bar mol) and b = 0.00008 m³/mol.
=
Transcribed Image Text:A common way to extract work from changes in thermodynamic state is by flowing a gas through a turbine. initially at 100 bar and 600 K flowing rapidly through a turbine end exiting at Consider a real gas that 18 bar and 450 K. The following information is available. • The ideal-gas, constant-pressure heat capacity is cG/R = 3.6 +0.0024T [K] ap² T • The data for PuT is well represented by P(v − b) = RT + ● In the above, a = 0.001 (m³K)/(bar mol) and b = 0.00008 m³/mol. =
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