nt main() { int n1=0,n2=1,n3,i,number; printf("Enter the number of elements:"); scanf("%d",&number); printf("\n%d %d",n1,n2);//printing 0 and 1 for(i=2;i
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- include<stdio.h>
- int main()
- {
- int n1=0,n2=1,n3,i,number;
- printf("Enter the number of elements:");
- scanf("%d",&number);
- printf("\n%d %d",n1,n2);//printing 0 and 1
- for(i=2;i<number;++i)//loop starts from 2 because 0 and 1 are already printed
- {
- n3=n1+n2;
- printf(" %d",n3);
- n1=n2;
- n2=n3;
- }
- return 0;
- } .
Output.
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Solved in 3 steps with 1 images
- Visual Basic.net) Write a Code that defines one dimensional arrays of ten elements that sums the even numbers from them and a counter that counts how many elements is an even number and comes out from the Loop when the sum of the even values becomes greater than 30 and the counter for these values is greater than 4. Write a program in Visual Basic.net .TRUE or FALSE IN JAVA You can obtain the number of rows using Array.length, and the number of columns in a specified row using array[row].length.q3/write program in c++ language read 2D array and print the elements that are not divisible 7 _le aaudll Jaid *
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